Experiment 5 Physics Lab Report 3mv2v

EXPERIMENT 5 CENTER OF GRAVITY AND EQUILIBRIUM 2F – MT Group 3 #15 Eroles, Ruzelle #16 Espineli, Sharika Mae #17 Fernando, Kamilah #18 Galapon, Chester Bill #19 Galinato, Jeana May #20 Garcia, Jairish Keith

beam. In set-up B, the initial system where the point of is measured and placed at mark 30 cm then by placing weights 200 g, 100 g and 20 g at marks 10 cm, 20 cm and 90 cm respectively. Lastly, by using a 50 g weight and by positioning it at a certain point at the right side of the set-up, the combination of the weight and distance must bring the said set-up to rotational equilibrium.

GUIDE QUESTIONS 1. Define the following:

ABSTRACT The center of gravity is the location of the average position of the mass in the object. In other words, it is the mean position of the mass in a certain system. Another concept used in this experiment is the concept of torque which is the capability of rotating objects around a fixed axis. When dealing with torques, the concept of equilibrium is still present. An object can be acted on by several torques at a time. If the size and direction of the torques acting on the object are exactly balanced, then there is no net torque acting on the object and the object is said to be in equilibrium. The concepts of center of gravity, equilibrium and torque is applied in this experiment. In set-up A, the meter stick was put into equilibrium and then adjusted in another manner in which the point of is placed in another location. Then, using the weights, the set-up was brought again into equilibrium by adjusting the weight used in such a way that the meter stick would again be balanced. This was performed in order to observe how the weight of the beam on which the forces act behaves like a force concentrated at the center of gravity of the

a. the moment of a force - The moment of a force, also called torque, is the measure of a force’s tendency to produce torsion and rotation about an axis, equal to the vector product of the radius vector from the axis of rotation to the point of application of the force and the force vector. b. the center of gravity - It is the point at which the entire weight of a body may be considered as concentrated so that if ed at this point the body would remain in equilibrium in any position. 2. Differentiate translational and rotational equilibrium. Translational equilibrium is a balanced system in which it remains at rest and is not moving in any direction along a plane. It relates to any forces on any object. It is when all the forces acting on a particular object add up to zero and have no resultant force. Rotational equilibrium, on the other hand, is a balanced system in which it not moving clockwise or counter clockwise and the total angular acceleration is zero.

3. A uniform rod 1.00 m long weighs 150.0 N and is ed on some fulcrum. Weights of 40.0 N and 50.0 N are suspended from the two ends of the rod. Find the position of the fulcrum if the system is in equilibrium.

P + R = F1l1 + F2l2 + F3l3 + F4l4 If fulcrum is placed on R: P = (250N)(7m) + (150N)(3m) + (100N)(1m) + (120)(2m)

0.5 + x

P = 2540 N x

FPlP = 2540 N FP (6m) = 2540 N

150 N

40 N

50 N

0.5 – x

FP = 423.33 N If fulcrum is placed on P:

40 (0.5 + x) + 150 (x) – 50 (0.5 – x) = 0

R = (250N)(1m) + (150N)(3m) + (100N)(5m) + (120)(8m) R = 2160 N

20 + 40x + 150x – 25 + 50x = 0

FRlR = 2160 N

- 5 + 240x = 0

FR (6m) = 2160 N

- 5 = - 240x

FR = 360 N

x = 0.0208 m

CONCLUSION

0.5 + x: 0.5 + 0.0208 m = 0.5208 m 0.5 – x: 0.5 – 0.0208 m = 0.4792 m 4. A uniform rod 10.0 m long and weighing 150.0 N is ed horizontally by props P and R a distance of 2.0 m and 8.0 m from one end. Weights of 250.0 N, 100.0 N and 120.0 N are attached at distances of 1 m, 7 m and 10 m respectively from the same end. Find the force on each prop. F1=250 N N 2 cm

1 cm

P

F3 = 100 N F4 = 120 5 cm

SOURCES https://www.udemy.com/blog/translationalequilibrium/ http://www.merriamwebster.com/dictionary/center%20of%20gravit y http://www.thefreedictionary.com/Moment+of +force

8 cm

F2 = 150 N 7 cm R

From the experiment performed, the relationship of equilibrium, torque and center of gravity has been shown. Both set-ups achieved equilibrium after adjusting certain elements in the system. All objectives in the said experiment were achieved.

10 cm

http://www.grc.nasa.gov/WWW/k12/airplane/equilibt.html