Heating Coil Calculation 5s5q73
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Specific heat of finished good
= =
S.G of finished goods =
0.87
Mass of finished goods
= m =
0.47
865.4
kcal/kg/k =
=
12.69
= v
Re = (VD)/ν =
867.2
specific heat of thermic fluid
Prantdl number = Pr = v/α hi = 48k/11d =
13.6
300 cst =
0
m2/s
0.88
=
0
kW/m-K
kg/m3
= =
Thermal diffusivity of thermic fluid
=
1729.48
thermal conductivity of thermal fluid = density of thermic fluid =
m2
m/sec
kinematic viscosity of thermic fluid Reynolds number
kW
60 m3/hr
Internal dia of coil D = 40.9 mm Crossectional area of coil = 0 velocity of flow V =
kJ/kg-K
kg
Amount of heat to be provided to Finished goods = m∆T = 68001.28 Flow rate of thermic fluid
1.96
0.54
Kcal/kg-K =
= α = k/(ρ) =
kW/m2-k
4584.28
=
2.25 0
kJ/kg-k m2/s
= =
S.G of finished goods =
0.87
Mass of finished goods
= m =
0.47
865.4
kcal/kg/k =
=
12.69
= v
Re = (VD)/ν =
867.2
specific heat of thermic fluid
Prantdl number = Pr = v/α hi = 48k/11d =
13.6
300 cst =
0
m2/s
0.88
=
0
kW/m-K
kg/m3
= =
Thermal diffusivity of thermic fluid
=
1729.48
thermal conductivity of thermal fluid = density of thermic fluid =
m2
m/sec
kinematic viscosity of thermic fluid Reynolds number
kW
60 m3/hr
Internal dia of coil D = 40.9 mm Crossectional area of coil = 0 velocity of flow V =
kJ/kg-K
kg
Amount of heat to be provided to Finished goods = m∆T = 68001.28 Flow rate of thermic fluid
1.96
0.54
Kcal/kg-K =
= α = k/(ρ) =
kW/m2-k
4584.28
=
2.25 0
kJ/kg-k m2/s
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