Irwin, Basic Engineering Circuit Analysis, 11/e Chapter 1, Solution q104t
This document was ed by and they confirmed that they have the permission to share it. If you are author or own the copyright of this book, please report to us by using this report form. Report 3i3n4
Overview 26281t
& View Irwin, Basic Engineering Circuit Analysis, 11/e Chapter 1, Solution as PDF for free.
More details 6y5l6z
- Words: 2,799
- Pages: 52
Irwin, Basic Engineering Circuit Analysis, 11/E
1
1.1 If the current in an electric conductor is 2.4 A, how many c oulombs of charge any point in a 30-second interval?
SOLUTION:
Chapter 01: Basic Concepts
Problem 1.1
Irwin, Basic Engineering Circuit Analysis, 11/E
1
1.2 Determine the time interval required for a 12-A battery charger to deliver 4800 C.
SOLUTION:
Chapter 01: Basic Concepts
Problem 1.2
Irwin, Basic Engineering Circuit Analysis, 11/E
1
1.3 A lightning bolt carrying 30,000 A lasts for 50 micro-seconds. If the lightning strikes an airplane flying at 20,000
feet, what is the charge deposited on the plane?
SOLUTION:
Chapter 01: Basic Concepts
Problem 1.3
Irwin, Basic Engineering Circuit Analysis, 11/E
1
1.4 If a 12-V battery delivers 100 J in 5 s, find (a) the amount of charge delivered and (b) the current produced.
SOLUTION:
Chapter 01: Basic Concepts
Problem 1.4
Irwin, Basic Engineering Circuit Analysis, 11/E
1
1.5 The current in a conductor is 1.5 A. How many coulombs of charge any point in a time interval of 1.5 minutes?
SOLUTION:
Chapter 01: Basic Concepts
Problem 1.5
Irwin, Basic Engineering Circuit Analysis, 11/E
1
1.6 If 60 C of charge through an electric conductor in 30 seconds, determine the current in the conductor.
SOLUTION:
Chapter 01: Basic Concepts
Problem 1.6
Irwin, Basic Engineering Circuit Analysis, 11/E
1
1.7 Determine the number of coulombs of charge produced by a 12-A battery charger in an hour.
SOLUTION:
Chapter 01: Basic Concepts
Problem 1.7
Irwin, Basic Engineering Circuit Analysis, 11/E
1
1.8 Five coulombs of charge through the element in Fig. P1.8 from point A to point B. If the energy absorbed by
the element is 120 J, determine the voltage across the element. B + V1
− A Figure P1.8
SOLUTION:
Chapter 01: Basic Concepts
Problem 1.8
Irwin, Basic Engineering Circuit Analysis, 11/E
1
1.9 T he current that enters an element is shown in Fig. P1.9. Find the charge that enters the element in the time
interval 0 < t < 20 s. i(t) mA 10
0
10
20
t (s)
Figure P1.9
SOLUTION:
Chapter 01: Basic Concepts
Problem 1.9
Irwin, Basic Engineering Circuit Analysis, 11/E
1
1.10 T he charge entering the positive terminal of an element is q(t) = −30e− 4tmC. If the voltage across the element
is 120e−2 tV, determine the energy delivered to the element in the time interval 0 < t < 50 ms.
SOLUTION:
Chapter 01: Basic Concepts
Problem 1.10
Irwin, Basic Engineering Circuit Analysis, 11/E
1
1.11 T he charge entering the positive terminal of an element is given by the expression q(t) = −12e−2tmC. The
power delivered to the element is p(t) = 2.4e− 3tW. Compute the current in the element, the voltage across the element, and the energy delivered to the element in the time interval 0 < t < 100 ms.
SOLUTION:
Chapter 01: Basic Concepts
Problem 1.11
Irwin, Basic Engineering Circuit Analysis, 11/E
1
1.12 T he voltage across an element is 12e− 2tV. The current entering the positive terminal of the element is 2e− 2tA.
Find the energy absorbed by the element in 1.5 s starting from t = 0.
SOLUTION:
Chapter 01: Basic Concepts
Problem 1.12
Irwin, Basic Engineering Circuit Analysis, 11/E
1
1.13 T he power absorbed by the BOX in Fig. P1.13 is 2e− 2tW. Calculate the amount of charge that enters the BOX
between 0.1 and 0.4 seconds.
4e−t V
+ −
BOX
Figure P1.13
SOLUTION:
Chapter 01: Basic Concepts
Problem 1.13
Irwin, Basic Engineering Circuit Analysis, 11/E
1
1.14 T he power absorbed by the BOX in Fig. P1.14 is 0.1e− 4tW. Calculate the energy absorbed by the BOX during
this same time interval.
10e−2t V
+ −
BOX
Figure P1.14
SOLUTION:
Chapter 01: Basic Concepts
Problem 1.14
Irwin, Basic Engineering Circuit Analysis, 11/E
1
i (t) + −
15 V
BOX
1.15 T he energy absorbed by the BOX in Fig. P1.15 is shown below. How much charge enters the BOX between
0 and 10 milliseconds? i (t)
w(t) (mJ) 15
15 V
+ −
BOX 10 5
w(t) (mJ) 15
1
2
3
4
5
6
7
8
9
10
t (ms)
−5
10
−10
5 −15
1
2
3 Figure 4 P1.15 5
6
7
8
9
10
t (ms)
−5 −10
SOLUTION:
−15
Chapter 01: Basic Concepts
Problem 1.15
2
Problem 1.15
Irwin, Basic Engineering Circuit Analysis, 11/E
Chapter 01: Basic Concepts
Irwin, Basic Engineering Circuit Analysis, 11/E
1 i (t) +
12 V
BOX
− Calculate and sketch 1.16 T he charge that enters the BOX in Fig. P1.16 is shown in the graph below.
the current flowing into and the power absorbed by the BOX between 0 and 10 milliseconds. i (t)
q(t) (mC)
+ −
12 V
3
BOX
2 1
q(t) (mC)
5
3
1
2
3
4
6
7
8
9
10
t (ms)
−1
2
−2
1 5 1
2
3
4
−3
6
7
8
9
10
t (ms)
−1 −2
Figure P1.16
−3
SOLUTION:
Chapter 01: Basic Concepts
Problem 1.16
2
Problem 1.16
Irwin, Basic Engineering Circuit Analysis, 11/E
Chapter 01: Basic Concepts
Irwin, Basic Engineering Circuit Analysis, 11/E
Chapter 01: Basic Concepts
3
Problem 1.16
Irwin, Basic Engineering Circuit Analysis, 11/E
1 i (t)
1.17 T he energy absorbed by the BOX in Fig. P1.17 is given below. Calculate and sketch the current flowing into BOX 10 V0 + the BOX. Also calculate the charge which enters the BOX between and 12 seconds. −
i (t)
10 V
w(t) (J)
+ −
BOX
5
6 1
w(t) (J)
2
3
4
5
7
8
10 9
12 11
t (s)
−2.5
5
Figure P1.17
6 1
2
3
4
7
5
8
10 9
12 11
t (s)
−2.5
SOLUTION:
Chapter 01: Basic Concepts
Problem 1.17
2
Problem 1.17
Irwin, Basic Engineering Circuit Analysis, 11/E
Chapter 01: Basic Concepts
Irwin, Basic Engineering Circuit Analysis, 11/E
1
i (t)
12 V
+
BOX
− 1.18 T he charge entering the upper terminal of the BOX in Fig. P1.18 is shown below. How much energy is absorbed
by the BOX between 0 and 9 seconds? q(t) (C)
i (t) 1
12 V
+ −
BOX 0.5
1
q(t) (C)
2
3
4
5
6
7
8
9
t (s)
−0.5
1
−1 −1.5
0.5
1
2
Figure P1.18 3 4 5
6
7
8
9
t (s)
−0.5 −1 −1.5
SOLUTION:
Chapter 01: Basic Concepts
Problem 1.18
2
Problem 1.18
Irwin, Basic Engineering Circuit Analysis, 11/E
Chapter 01: Basic Concepts
Irwin, Basic Engineering Circuit Analysis, 11/E
1 i (t)
1.19 T he energy absorbed by the BOX in Fig. P1.19 is shown in the graph below. Calculate and sketch the current + BOX 12 V
flowing into the BOX between 0 and 10 milliseconds. i (t)
−
w(t) (mJ) 30
12 V
+ −
BOX
20 10 5
w(t) (mJ) 1
30
2
3
4
6
7 8
9
10
t (ms)
−10
20
−20
10
−30
5 1
2
6
3 4 Figure P1.19
7 8
9
10
t (ms)
−10 −20 −30
SOLUTION:
Chapter 01: Basic Concepts
Problem 1.19
2
Problem 1.19
Irwin, Basic Engineering Circuit Analysis, 11/E
Chapter 01: Basic Concepts
Irwin, Basic Engineering Circuit Analysis, 11/E
1
1.20 D etermine the amount of power absorbed or supplied by the element in Fig. P1.20 if (a) V1 = 9 V and I = 2A (b) V1 = 9 V and I = −3A (c) V1 = −12 V and I = 2A (d) V1 = −12 V and I = −3A
+
I
V1
−
Figure P1.20
SOLUTION:
Chapter 01: Basic Concepts
Problem 1.20
Irwin, Basic Engineering Circuit Analysis, 11/E
1
1.21 C alculate the power absorbed by element A in Fig. P1.21. 3A − 15 V
A +
Figure P1.21
SOLUTION:
Chapter 01: Basic Concepts
Problem 1.21
Irwin, Basic Engineering Circuit Analysis, 11/E
1
1.22 C alculate the power supplied by element A in Fig. P1.22. 2A + 20 V
A −
Figure P1.22
SOLUTION:
Chapter 01: Basic Concepts
Problem 1.22
Irwin, Basic Engineering Circuit Analysis, 11/E
1
1.23 E lement A in the diagram in Fig. P1.23 absorbs 30 W of power. Calculate V x . 2A + Vx
A −
Figure P1.23
SOLUTION:
Chapter 01: Basic Concepts
Problem 1.23
Irwin, Basic Engineering Circuit Analysis, 11/E
1
1.24 E lement B in the diagram in Fig. P1.24 supplies 60 W of power. Calculate I x .
− 24 V
B +
Ix
Figure P1.24
SOLUTION:
Chapter 01: Basic Concepts
Problem 1.24
Irwin, Basic Engineering Circuit Analysis, 11/E
1
1.25 E lement B in the diagram in Fig. P1.25 supplies 72 W of power. Calculate V A . 3A + VA B –
Figure P1.25
SOLUTION:
Chapter 01: Basic Concepts
Problem 1.25
Irwin, Basic Engineering Circuit Analysis, 11/E
1.26 E lement B in the diagram in Fig. P1.26 supplies 72 W of power. Calculate
1
Ix.
+ 18 V B −
Ix
Figure P1.26
SOLUTION:
Chapter 01: Basic Concepts
Problem 1.26
Irwin, Basic Engineering Circuit Analysis, 11/E
1
P1 = 36 W. Is element 2 absorbing or supplying power, and how much? (b) In Fig. P1.27 (b), P2 = −48 W. Is element 1 absorbing or supplying power, and how much? 1.27 (a) In Fig. P1.27 (a),
1 2
+ 12 V − + 6V −
(a)
1 2
− 6V + + 24 V −
(b)
Figure P1.27
SOLUTION:
Chapter 01: Basic Concepts
Problem 1.27
Irwin, Basic Engineering Circuit Analysis, 11/E
1
1.28 T wo elements are connected in series, as shown in Fig. P1.28. Element 1 supplies 24 W of power. Is element 2
absorbing or supplying power, and how much?
1
2
+ 3V − − 6V +
Figure P1.28
SOLUTION:
Chapter 01: Basic Concepts
Problem 1.28
Irwin, Basic Engineering Circuit Analysis, 11/E
1
1.29 E lement 2 in Fig. P1.29 absorbed 32 W. Find the power absorbed or supplied by elements 1 and 3. − 4V + + 2 8V − + 3 12 V − 1
Figure P1.29
SOLUTION:
Chapter 01: Basic Concepts
Problem 1.29
Irwin, Basic Engineering Circuit Analysis, 11/E
1.30 C hoose
Is such that the power absorbed by element 2 in Fig. P1.30 is 7 W. +
4V 1
−
− +
+ 6V
1
Is
2 2V −
Figure P1.30
SOLUTION:
Chapter 01: Basic Concepts
Problem 1.30
Irwin, Basic Engineering Circuit Analysis, 11/E
1
1.31 F ind the power that is absorbed or supplied by the circuit elements in Fig. P1.31. +
6V 1
+ 20 V
Ix = 4 A
− 2A
+ −
2A −
+
8V 1
+ 14 V
16 V
+ −
4A −
+
6V 1
+
V
+ −
2A −
(a)
Ix = 4 A
− 2A
+
8V 1
(b) −
+ 14 V
16 V
+ −
4A −
2Ix 4A
2A (a)
2Ix 4A
2A
−
(b)
Figure P1.31
SOLUTION:
Chapter 01: Basic Concepts
Problem 1.31
Irwin, Basic Engineering Circuit Analysis, 11/E
1
1.32 F ind the power that is absorbed or supplied by the network elements in Fig. P1.32. Ix = 2 A +
8V 1
−2A
+ −
+ −
12 V
2Ix 2A
(a) 24 V −+ 2A + −
+ 2A
20 V 1
− Ix = 2 A +
4Ix
2
12 V −
2A
(b)
Figure P1.32
SOLUTION:
Chapter 01: Basic Concepts
Problem 1.32
Irwin, Basic Engineering Circuit Analysis, 11/E
1
1.33 Compute the power that is absorbed or supplied by the e lements in the network in Fig. P1.33. Ix = 4 A +
12 V
1Ix
−
−+
1 2A
36 V
+ −
2
+ 24 V −
2A + 3 28 V −
Figure P1.33
SOLUTION:
Chapter 01: Basic Concepts
Problem 1.33
Irwin, Basic Engineering Circuit Analysis, 11/E
1
1.34 Find the power that is absorbed or supplied by element 2 in Fig. P1.34. 2A +
4V 1
2Vx
−
−+ +
12 V + −
2 −
Vx
2A
Figure P1.34
SOLUTION:
Chapter 01: Basic Concepts
Problem 1.34
Irwin, Basic Engineering Circuit Analysis, 11/E
1
1.35 Find I x in the network in Fig. P1.35. 1Ix
Ix + 12 V − 1 2A 36 V
+ −
−+ + 2
24 V −
2A
+ 3
28 V −
Figure P1.35
SOLUTION:
Chapter 01: Basic Concepts
Problem 1.35
Irwin, Basic Engineering Circuit Analysis, 11/E
1
1.36 Determine the power absorbed by element 1 in Fig. P1.36. Ix +
12 V 1
−
+
+ 36 V
+ −
24 V −
2Ix
8V 2
− 2A + 3 16 V −
Figure P1.36
SOLUTION:
Chapter 01: Basic Concepts
Problem 1.36
Irwin, Basic Engineering Circuit Analysis, 11/E
1
1.37 Find the power absorbed or supplied by element 1 in Fig. P1.37. − Ix
6V 1
18 V + −
+
+
4V 2
−
2A 24 V
+ −
Ix
2Ix
+ 20 V −
Figure P1.37
SOLUTION:
Chapter 01: Basic Concepts
Problem 1.37
Irwin, Basic Engineering Circuit Analysis, 11/E
1
1.38 Find the power absorbed or supplied by element 3 in Fig. P1.38. +
4V 1
12 V
−
−+
4A
2A
+ 2
16 V −
+ −
12 V
+ −
4
2Vx + 3
2A
2A
−
Vx
+ 20 V − 2A
Figure P1.38
SOLUTION:
Chapter 01: Basic Concepts
Problem 1.38
Irwin, Basic Engineering Circuit Analysis, 11/E
1
1.39 Find the power absorbed or supplied by element 1 in Fig. P1.39. +
4V 1
12 V
−
−+
+ 4Ix
+ 12 V
−
2
8V − 4A
4A
+ 3
20 V − 2A
+ 4 Ix
20 V −
Figure P1.39
SOLUTION:
Chapter 01: Basic Concepts
Problem 1.39
Irwin, Basic Engineering Circuit Analysis, 11/E
1
1.40 F ind Vx in the network in Fig. P1.40 using Tellegen’s theorem. 2A + 9V
+ 1 12 V
−
−+
2
24 V
+ V − x
− +
16 V
−
3 − +
12 V
Figure P1.40
SOLUTION:
Chapter 01: Basic Concepts
Problem 1.40
Irwin, Basic Engineering Circuit Analysis, 11/E
Ix in the circuit in Fig. P1.41 using Tellegen’s theorem.
2A +
4V
−
+
8V
−
+
18 V
2A + −
24 V
+ 12 V −
12 V
− Ix
2A
+−
1.41 Find
1
Ix
+ 6V −
Figure P1.41
SOLUTION:
Chapter 01: Basic Concepts
Problem 1.41
Irwin, Basic Engineering Circuit Analysis, 11/E
1.42 Is the source +
Vs in the network in Fig. P1.42 absorbing or supplying power, and how much? 6V
3A
VS
−
−+
9A
6A −
−
− 10 V +
1
9A 3A
16 V +
8V +
Figure P1.42
SOLUTION:
Chapter 01: Basic Concepts
Problem 1.42
Irwin, Basic Engineering Circuit Analysis, 11/E
1.43 F ind
Io in the network in Fig. P1.43 using Tellegen’s theorem. 6A+
24 V
4Ix
8V 1
− 4A +
+ −
2 −
6V 3
10 V −
Io
8V 6
4 16 V −
+ 6V
5 −
Ix=2 A +
+
+ −
3A
1
− +
1A
3A
Figure P1.43
SOLUTION:
Chapter 01: Basic Concepts
Problem 1.43
Irwin, Basic Engineering Circuit Analysis, 11/E
1
1.44 C alculate the power absorbed by each element in the circuit in Fig. P1.44. Also, that Tellegen’s theorem is
satisfied by this circuit. 3Ix
+
−+
24 V 5
− 2A
2A +
24 V
12 V 1
+ −
−
+
2A + 12 V
4A
4A 6A
−
6V 2
− + 6V 3 −
−
9V 4
+ 4A
15 V
+ −
Ix = 2 A
Figure P1.44
SOLUTION:
Chapter 01: Basic Concepts
Problem 1.44
Irwin, Basic Engineering Circuit Analysis, 11/E
1
1.45 C alculate the power absorbed by each element in the circuit in Fig. P1.45. Also, that Tellegen’s theorem is
satisfied by this circuit. +
4A
+ 1A 40 V
2
3
−
+ −
−
+
1
5V 4
− 3A
4A
30 V −
+
+ −
15 V
+ 5A
− 5V
5V
10 V
1A
+ 5
10 V −
Figure P1.45
SOLUTION:
Chapter 01: Basic Concepts
Problem 1.45
Irwin, Basic Engineering Circuit Analysis, 11/E
1
1.46 In the circuit in Fig. P1.46, element 1 absorbs 40 W, element 2 supplies 50 W, element 3 supplies 25 W, and
element 4 absorbs 15 W. How much power is supplied by element 5? 1
3
2
4
5
Figure P1.46
SOLUTION:
Chapter 01: Basic Concepts
Problem 1.46
1
1.1 If the current in an electric conductor is 2.4 A, how many c oulombs of charge any point in a 30-second interval?
SOLUTION:
Chapter 01: Basic Concepts
Problem 1.1
Irwin, Basic Engineering Circuit Analysis, 11/E
1
1.2 Determine the time interval required for a 12-A battery charger to deliver 4800 C.
SOLUTION:
Chapter 01: Basic Concepts
Problem 1.2
Irwin, Basic Engineering Circuit Analysis, 11/E
1
1.3 A lightning bolt carrying 30,000 A lasts for 50 micro-seconds. If the lightning strikes an airplane flying at 20,000
feet, what is the charge deposited on the plane?
SOLUTION:
Chapter 01: Basic Concepts
Problem 1.3
Irwin, Basic Engineering Circuit Analysis, 11/E
1
1.4 If a 12-V battery delivers 100 J in 5 s, find (a) the amount of charge delivered and (b) the current produced.
SOLUTION:
Chapter 01: Basic Concepts
Problem 1.4
Irwin, Basic Engineering Circuit Analysis, 11/E
1
1.5 The current in a conductor is 1.5 A. How many coulombs of charge any point in a time interval of 1.5 minutes?
SOLUTION:
Chapter 01: Basic Concepts
Problem 1.5
Irwin, Basic Engineering Circuit Analysis, 11/E
1
1.6 If 60 C of charge through an electric conductor in 30 seconds, determine the current in the conductor.
SOLUTION:
Chapter 01: Basic Concepts
Problem 1.6
Irwin, Basic Engineering Circuit Analysis, 11/E
1
1.7 Determine the number of coulombs of charge produced by a 12-A battery charger in an hour.
SOLUTION:
Chapter 01: Basic Concepts
Problem 1.7
Irwin, Basic Engineering Circuit Analysis, 11/E
1
1.8 Five coulombs of charge through the element in Fig. P1.8 from point A to point B. If the energy absorbed by
the element is 120 J, determine the voltage across the element. B + V1
− A Figure P1.8
SOLUTION:
Chapter 01: Basic Concepts
Problem 1.8
Irwin, Basic Engineering Circuit Analysis, 11/E
1
1.9 T he current that enters an element is shown in Fig. P1.9. Find the charge that enters the element in the time
interval 0 < t < 20 s. i(t) mA 10
0
10
20
t (s)
Figure P1.9
SOLUTION:
Chapter 01: Basic Concepts
Problem 1.9
Irwin, Basic Engineering Circuit Analysis, 11/E
1
1.10 T he charge entering the positive terminal of an element is q(t) = −30e− 4tmC. If the voltage across the element
is 120e−2 tV, determine the energy delivered to the element in the time interval 0 < t < 50 ms.
SOLUTION:
Chapter 01: Basic Concepts
Problem 1.10
Irwin, Basic Engineering Circuit Analysis, 11/E
1
1.11 T he charge entering the positive terminal of an element is given by the expression q(t) = −12e−2tmC. The
power delivered to the element is p(t) = 2.4e− 3tW. Compute the current in the element, the voltage across the element, and the energy delivered to the element in the time interval 0 < t < 100 ms.
SOLUTION:
Chapter 01: Basic Concepts
Problem 1.11
Irwin, Basic Engineering Circuit Analysis, 11/E
1
1.12 T he voltage across an element is 12e− 2tV. The current entering the positive terminal of the element is 2e− 2tA.
Find the energy absorbed by the element in 1.5 s starting from t = 0.
SOLUTION:
Chapter 01: Basic Concepts
Problem 1.12
Irwin, Basic Engineering Circuit Analysis, 11/E
1
1.13 T he power absorbed by the BOX in Fig. P1.13 is 2e− 2tW. Calculate the amount of charge that enters the BOX
between 0.1 and 0.4 seconds.
4e−t V
+ −
BOX
Figure P1.13
SOLUTION:
Chapter 01: Basic Concepts
Problem 1.13
Irwin, Basic Engineering Circuit Analysis, 11/E
1
1.14 T he power absorbed by the BOX in Fig. P1.14 is 0.1e− 4tW. Calculate the energy absorbed by the BOX during
this same time interval.
10e−2t V
+ −
BOX
Figure P1.14
SOLUTION:
Chapter 01: Basic Concepts
Problem 1.14
Irwin, Basic Engineering Circuit Analysis, 11/E
1
i (t) + −
15 V
BOX
1.15 T he energy absorbed by the BOX in Fig. P1.15 is shown below. How much charge enters the BOX between
0 and 10 milliseconds? i (t)
w(t) (mJ) 15
15 V
+ −
BOX 10 5
w(t) (mJ) 15
1
2
3
4
5
6
7
8
9
10
t (ms)
−5
10
−10
5 −15
1
2
3 Figure 4 P1.15 5
6
7
8
9
10
t (ms)
−5 −10
SOLUTION:
−15
Chapter 01: Basic Concepts
Problem 1.15
2
Problem 1.15
Irwin, Basic Engineering Circuit Analysis, 11/E
Chapter 01: Basic Concepts
Irwin, Basic Engineering Circuit Analysis, 11/E
1 i (t) +
12 V
BOX
− Calculate and sketch 1.16 T he charge that enters the BOX in Fig. P1.16 is shown in the graph below.
the current flowing into and the power absorbed by the BOX between 0 and 10 milliseconds. i (t)
q(t) (mC)
+ −
12 V
3
BOX
2 1
q(t) (mC)
5
3
1
2
3
4
6
7
8
9
10
t (ms)
−1
2
−2
1 5 1
2
3
4
−3
6
7
8
9
10
t (ms)
−1 −2
Figure P1.16
−3
SOLUTION:
Chapter 01: Basic Concepts
Problem 1.16
2
Problem 1.16
Irwin, Basic Engineering Circuit Analysis, 11/E
Chapter 01: Basic Concepts
Irwin, Basic Engineering Circuit Analysis, 11/E
Chapter 01: Basic Concepts
3
Problem 1.16
Irwin, Basic Engineering Circuit Analysis, 11/E
1 i (t)
1.17 T he energy absorbed by the BOX in Fig. P1.17 is given below. Calculate and sketch the current flowing into BOX 10 V0 + the BOX. Also calculate the charge which enters the BOX between and 12 seconds. −
i (t)
10 V
w(t) (J)
+ −
BOX
5
6 1
w(t) (J)
2
3
4
5
7
8
10 9
12 11
t (s)
−2.5
5
Figure P1.17
6 1
2
3
4
7
5
8
10 9
12 11
t (s)
−2.5
SOLUTION:
Chapter 01: Basic Concepts
Problem 1.17
2
Problem 1.17
Irwin, Basic Engineering Circuit Analysis, 11/E
Chapter 01: Basic Concepts
Irwin, Basic Engineering Circuit Analysis, 11/E
1
i (t)
12 V
+
BOX
− 1.18 T he charge entering the upper terminal of the BOX in Fig. P1.18 is shown below. How much energy is absorbed
by the BOX between 0 and 9 seconds? q(t) (C)
i (t) 1
12 V
+ −
BOX 0.5
1
q(t) (C)
2
3
4
5
6
7
8
9
t (s)
−0.5
1
−1 −1.5
0.5
1
2
Figure P1.18 3 4 5
6
7
8
9
t (s)
−0.5 −1 −1.5
SOLUTION:
Chapter 01: Basic Concepts
Problem 1.18
2
Problem 1.18
Irwin, Basic Engineering Circuit Analysis, 11/E
Chapter 01: Basic Concepts
Irwin, Basic Engineering Circuit Analysis, 11/E
1 i (t)
1.19 T he energy absorbed by the BOX in Fig. P1.19 is shown in the graph below. Calculate and sketch the current + BOX 12 V
flowing into the BOX between 0 and 10 milliseconds. i (t)
−
w(t) (mJ) 30
12 V
+ −
BOX
20 10 5
w(t) (mJ) 1
30
2
3
4
6
7 8
9
10
t (ms)
−10
20
−20
10
−30
5 1
2
6
3 4 Figure P1.19
7 8
9
10
t (ms)
−10 −20 −30
SOLUTION:
Chapter 01: Basic Concepts
Problem 1.19
2
Problem 1.19
Irwin, Basic Engineering Circuit Analysis, 11/E
Chapter 01: Basic Concepts
Irwin, Basic Engineering Circuit Analysis, 11/E
1
1.20 D etermine the amount of power absorbed or supplied by the element in Fig. P1.20 if (a) V1 = 9 V and I = 2A (b) V1 = 9 V and I = −3A (c) V1 = −12 V and I = 2A (d) V1 = −12 V and I = −3A
+
I
V1
−
Figure P1.20
SOLUTION:
Chapter 01: Basic Concepts
Problem 1.20
Irwin, Basic Engineering Circuit Analysis, 11/E
1
1.21 C alculate the power absorbed by element A in Fig. P1.21. 3A − 15 V
A +
Figure P1.21
SOLUTION:
Chapter 01: Basic Concepts
Problem 1.21
Irwin, Basic Engineering Circuit Analysis, 11/E
1
1.22 C alculate the power supplied by element A in Fig. P1.22. 2A + 20 V
A −
Figure P1.22
SOLUTION:
Chapter 01: Basic Concepts
Problem 1.22
Irwin, Basic Engineering Circuit Analysis, 11/E
1
1.23 E lement A in the diagram in Fig. P1.23 absorbs 30 W of power. Calculate V x . 2A + Vx
A −
Figure P1.23
SOLUTION:
Chapter 01: Basic Concepts
Problem 1.23
Irwin, Basic Engineering Circuit Analysis, 11/E
1
1.24 E lement B in the diagram in Fig. P1.24 supplies 60 W of power. Calculate I x .
− 24 V
B +
Ix
Figure P1.24
SOLUTION:
Chapter 01: Basic Concepts
Problem 1.24
Irwin, Basic Engineering Circuit Analysis, 11/E
1
1.25 E lement B in the diagram in Fig. P1.25 supplies 72 W of power. Calculate V A . 3A + VA B –
Figure P1.25
SOLUTION:
Chapter 01: Basic Concepts
Problem 1.25
Irwin, Basic Engineering Circuit Analysis, 11/E
1.26 E lement B in the diagram in Fig. P1.26 supplies 72 W of power. Calculate
1
Ix.
+ 18 V B −
Ix
Figure P1.26
SOLUTION:
Chapter 01: Basic Concepts
Problem 1.26
Irwin, Basic Engineering Circuit Analysis, 11/E
1
P1 = 36 W. Is element 2 absorbing or supplying power, and how much? (b) In Fig. P1.27 (b), P2 = −48 W. Is element 1 absorbing or supplying power, and how much? 1.27 (a) In Fig. P1.27 (a),
1 2
+ 12 V − + 6V −
(a)
1 2
− 6V + + 24 V −
(b)
Figure P1.27
SOLUTION:
Chapter 01: Basic Concepts
Problem 1.27
Irwin, Basic Engineering Circuit Analysis, 11/E
1
1.28 T wo elements are connected in series, as shown in Fig. P1.28. Element 1 supplies 24 W of power. Is element 2
absorbing or supplying power, and how much?
1
2
+ 3V − − 6V +
Figure P1.28
SOLUTION:
Chapter 01: Basic Concepts
Problem 1.28
Irwin, Basic Engineering Circuit Analysis, 11/E
1
1.29 E lement 2 in Fig. P1.29 absorbed 32 W. Find the power absorbed or supplied by elements 1 and 3. − 4V + + 2 8V − + 3 12 V − 1
Figure P1.29
SOLUTION:
Chapter 01: Basic Concepts
Problem 1.29
Irwin, Basic Engineering Circuit Analysis, 11/E
1.30 C hoose
Is such that the power absorbed by element 2 in Fig. P1.30 is 7 W. +
4V 1
−
− +
+ 6V
1
Is
2 2V −
Figure P1.30
SOLUTION:
Chapter 01: Basic Concepts
Problem 1.30
Irwin, Basic Engineering Circuit Analysis, 11/E
1
1.31 F ind the power that is absorbed or supplied by the circuit elements in Fig. P1.31. +
6V 1
+ 20 V
Ix = 4 A
− 2A
+ −
2A −
+
8V 1
+ 14 V
16 V
+ −
4A −
+
6V 1
+
V
+ −
2A −
(a)
Ix = 4 A
− 2A
+
8V 1
(b) −
+ 14 V
16 V
+ −
4A −
2Ix 4A
2A (a)
2Ix 4A
2A
−
(b)
Figure P1.31
SOLUTION:
Chapter 01: Basic Concepts
Problem 1.31
Irwin, Basic Engineering Circuit Analysis, 11/E
1
1.32 F ind the power that is absorbed or supplied by the network elements in Fig. P1.32. Ix = 2 A +
8V 1
−2A
+ −
+ −
12 V
2Ix 2A
(a) 24 V −+ 2A + −
+ 2A
20 V 1
− Ix = 2 A +
4Ix
2
12 V −
2A
(b)
Figure P1.32
SOLUTION:
Chapter 01: Basic Concepts
Problem 1.32
Irwin, Basic Engineering Circuit Analysis, 11/E
1
1.33 Compute the power that is absorbed or supplied by the e lements in the network in Fig. P1.33. Ix = 4 A +
12 V
1Ix
−
−+
1 2A
36 V
+ −
2
+ 24 V −
2A + 3 28 V −
Figure P1.33
SOLUTION:
Chapter 01: Basic Concepts
Problem 1.33
Irwin, Basic Engineering Circuit Analysis, 11/E
1
1.34 Find the power that is absorbed or supplied by element 2 in Fig. P1.34. 2A +
4V 1
2Vx
−
−+ +
12 V + −
2 −
Vx
2A
Figure P1.34
SOLUTION:
Chapter 01: Basic Concepts
Problem 1.34
Irwin, Basic Engineering Circuit Analysis, 11/E
1
1.35 Find I x in the network in Fig. P1.35. 1Ix
Ix + 12 V − 1 2A 36 V
+ −
−+ + 2
24 V −
2A
+ 3
28 V −
Figure P1.35
SOLUTION:
Chapter 01: Basic Concepts
Problem 1.35
Irwin, Basic Engineering Circuit Analysis, 11/E
1
1.36 Determine the power absorbed by element 1 in Fig. P1.36. Ix +
12 V 1
−
+
+ 36 V
+ −
24 V −
2Ix
8V 2
− 2A + 3 16 V −
Figure P1.36
SOLUTION:
Chapter 01: Basic Concepts
Problem 1.36
Irwin, Basic Engineering Circuit Analysis, 11/E
1
1.37 Find the power absorbed or supplied by element 1 in Fig. P1.37. − Ix
6V 1
18 V + −
+
+
4V 2
−
2A 24 V
+ −
Ix
2Ix
+ 20 V −
Figure P1.37
SOLUTION:
Chapter 01: Basic Concepts
Problem 1.37
Irwin, Basic Engineering Circuit Analysis, 11/E
1
1.38 Find the power absorbed or supplied by element 3 in Fig. P1.38. +
4V 1
12 V
−
−+
4A
2A
+ 2
16 V −
+ −
12 V
+ −
4
2Vx + 3
2A
2A
−
Vx
+ 20 V − 2A
Figure P1.38
SOLUTION:
Chapter 01: Basic Concepts
Problem 1.38
Irwin, Basic Engineering Circuit Analysis, 11/E
1
1.39 Find the power absorbed or supplied by element 1 in Fig. P1.39. +
4V 1
12 V
−
−+
+ 4Ix
+ 12 V
−
2
8V − 4A
4A
+ 3
20 V − 2A
+ 4 Ix
20 V −
Figure P1.39
SOLUTION:
Chapter 01: Basic Concepts
Problem 1.39
Irwin, Basic Engineering Circuit Analysis, 11/E
1
1.40 F ind Vx in the network in Fig. P1.40 using Tellegen’s theorem. 2A + 9V
+ 1 12 V
−
−+
2
24 V
+ V − x
− +
16 V
−
3 − +
12 V
Figure P1.40
SOLUTION:
Chapter 01: Basic Concepts
Problem 1.40
Irwin, Basic Engineering Circuit Analysis, 11/E
Ix in the circuit in Fig. P1.41 using Tellegen’s theorem.
2A +
4V
−
+
8V
−
+
18 V
2A + −
24 V
+ 12 V −
12 V
− Ix
2A
+−
1.41 Find
1
Ix
+ 6V −
Figure P1.41
SOLUTION:
Chapter 01: Basic Concepts
Problem 1.41
Irwin, Basic Engineering Circuit Analysis, 11/E
1.42 Is the source +
Vs in the network in Fig. P1.42 absorbing or supplying power, and how much? 6V
3A
VS
−
−+
9A
6A −
−
− 10 V +
1
9A 3A
16 V +
8V +
Figure P1.42
SOLUTION:
Chapter 01: Basic Concepts
Problem 1.42
Irwin, Basic Engineering Circuit Analysis, 11/E
1.43 F ind
Io in the network in Fig. P1.43 using Tellegen’s theorem. 6A+
24 V
4Ix
8V 1
− 4A +
+ −
2 −
6V 3
10 V −
Io
8V 6
4 16 V −
+ 6V
5 −
Ix=2 A +
+
+ −
3A
1
− +
1A
3A
Figure P1.43
SOLUTION:
Chapter 01: Basic Concepts
Problem 1.43
Irwin, Basic Engineering Circuit Analysis, 11/E
1
1.44 C alculate the power absorbed by each element in the circuit in Fig. P1.44. Also, that Tellegen’s theorem is
satisfied by this circuit. 3Ix
+
−+
24 V 5
− 2A
2A +
24 V
12 V 1
+ −
−
+
2A + 12 V
4A
4A 6A
−
6V 2
− + 6V 3 −
−
9V 4
+ 4A
15 V
+ −
Ix = 2 A
Figure P1.44
SOLUTION:
Chapter 01: Basic Concepts
Problem 1.44
Irwin, Basic Engineering Circuit Analysis, 11/E
1
1.45 C alculate the power absorbed by each element in the circuit in Fig. P1.45. Also, that Tellegen’s theorem is
satisfied by this circuit. +
4A
+ 1A 40 V
2
3
−
+ −
−
+
1
5V 4
− 3A
4A
30 V −
+
+ −
15 V
+ 5A
− 5V
5V
10 V
1A
+ 5
10 V −
Figure P1.45
SOLUTION:
Chapter 01: Basic Concepts
Problem 1.45
Irwin, Basic Engineering Circuit Analysis, 11/E
1
1.46 In the circuit in Fig. P1.46, element 1 absorbs 40 W, element 2 supplies 50 W, element 3 supplies 25 W, and
element 4 absorbs 15 W. How much power is supplied by element 5? 1
3
2
4
5
Figure P1.46
SOLUTION:
Chapter 01: Basic Concepts
Problem 1.46
Related Documents 3h463d
Irwin, Basic Engineering Circuit Analysis, 11/e Chapter 1, Solution q104t
November 2019 252
Basic Engineering Circuit Analysis Chapter 8 Solution 5l5l3v
October 2021 0
Irwin, Basic Engineering Circuit Analysis, 9e Solutions 2o6d1j
October 2019 77
Basic-engineering-circuit-analysis-10th-edition-irwin-solution-manual.pdf 3e3f2y
December 2019 30
Basic Engineering Circuit Analysis By Irwin Solution Manual 4q5w5
October 2019 133
Basic-engineering-circuit-analysis-10th-edition-irwin-solution-manual.pdf 3e3f2y
November 2019 47More Documents from "Ellen Pan" 5y214q
Irwin, Basic Engineering Circuit Analysis, 11/e Chapter 1, Solution q104t
November 2019 252
Erving Goffman Presentation Of Self In Everyday Life Pdf 4t4t62
October 2019 131
Comentario De Augusto De Prima Porta 2v1l2h
November 2019 50
Hormon Androgen 4q24v
September 2020 0
Resume Demokrasi 1c19e
December 2021 0