Lesson Plan in Mathematics 10 I. Objectives At the end of the lesson the students will be able to; 1. State the standard form of a circle with a formula for the equation of circle whose center is at the origin. 2. Solve problems involving circles on the coordinate plane. 3.
II. Subject Matter Topic
: Equation of a Circle: Equation of a Circle whose Equation is at the Center
References
: Spiral Math 10 pp. 198 – 199
Materials
: Visual Aids, Com, Ruler, cartolina
Values
: Accuracy,
III. Procedures: Teachers Activity A. Preparatory Activities 1. Greetings 2. Classroom Organization 3. Checking of Attendance B. Drill Activity: Let us see if you really understood our previous lesson. Class we will have an activity called The students will be divided into 4 groups. Each group will have a representative to pick out the illustrations inside the box. Using your knowledge about points on the plane of a circle, match the illustration on the equation provided. Illustration No. 1
Students Activity
The answer of the students will depend on what illustration they picked out.
2
2
X +Y <4
2
Illustration No. 2
X 2 +Y 2=3 2
Illustration No. 3
X 2 +Y 2 >4 2
Illustration No. 4
X 2 +Y 2=42
So class, is it clear? Any questions, clarifications? C. Review Activity:
None ma’am.
Class, do you the distance formula? Yes ma’am! It is How about the Pythagorean Theorem?
Correct! Now you are going to apply the distance formula or the Pythagorean theorem to solve the following problems, I will give you 4 minutes to answer the activity. This is an individual activity.
d=
y 2− y 1 ¿ 2 x 2−x 1 ¿2 +¿ ¿ √¿
c 2=a 2 + b2
A. What is the length of the segment shown on the coordinate plane below?
Using the Distance Formula 2
d=
y 2− y 1 ¿ x 2−x 1 ¿2 +¿ ¿ √¿ 2
=
d= 5
6−2 ¿ 2 7−4 ¿ +¿ ¿ √¿
B. Use the distance formula to determine the distance between points (12,15 ) and (4,9).
Very good class!
d=
y 2− y 1 ¿ 2 x 2−x 1 ¿2 +¿ ¿ √¿
=
9−15 ¿2 4−12 ¿2 +¿ ¿ √¿
d = 10 Are there any questions about our activity?
D. Motivation:
None ma’am.
Class I have here a circle puzzle. Your task is to figure out the radius. Only two measurements are given the hypotenuse of a right triangle inscribed in one quadrant of the circle and the distance of one vertex from the circumference of the circle. I will give you 2 minutes to figure out the answer. The radius of the circle is 8 inches. Notice that the given 8-inch line segment in the drawing is the diagonal of a rectangle embedded in the circle's quadrant. If you draw the other diagonal, you'll see it's the radius of the circle. The diagonals are necessarily equal, so the radius is 8 inches.
The students will answer differently, according to their own interpretation of the illustration.
IV. Lesson Proper: