Pedestal Design 5i241u
This document was ed by and they confirmed that they have the permission to share it. If you are author or own the copyright of this book, please report to us by using this report form. Report 3i3n4
Overview 26281t
& View Pedestal Design as PDF for free.
More details 6y5l6z
- Words: 3,757
- Pages: 18
PEDESTALS LOAD S-Static load D-Dynamic laod PEDESTALS BETWEEN GRID A & B IN GRID 2 & 3 Pedestal type P1 P1 P1
1 1 1
Type of pump CT make up pump DM Feed pump Domestic water pump
Load in each pedestal(kg) 1073 1718 1560
Nos 1 1
Type of pump Jockey pump FW pump motor driven
Static 1000(S) 1800(S)
Nos
IN GRID 3 & 4 Load(kg) Pedestal type P2 P1 IN GRID 4 &5 Load in each Pedestal type P6 P1 P7
Nos 2 2 2
Type of pump Diesel engine for FW pump FW pump DE driver FO tank
pedestal(kg) 1500 2700 500
Nos 1 1 1 1
Type of pump Diesel engine for FW pump FW pump DE driver FO tank FW pump motor driven
Load in each pedestal(kg) 800 2700 500 3950
Nos 1 1 1 1 1
Type of pump Jockey pump Domestic water pump (with motor) Dm feed pump ( with motor ) CT make up pump (with motor ) Decontainiation pump
Load in each pedestal(kg) 1600 1560 1718 1073 2000
IN GRID 5 & 6 Pedestal type P6 P1 P7 P1 IN GRID 5 & 6 Pedestal type P2 P1 P1 P1 P1
Dyamic 1600(D) 3950(D)
PEDESTALS BETWEEN GRID B &C IN GRID 2 & 3 Pedestal type P3 P3 P8
Nos Type of pump 1 Comp no.1 1 Comp no.2 2Hydro pnuematic tank
Load in each pedestal(kg) 1500 1500 14500
Nos 4
Type of pump Booster pump
Load in each pedestal(kg) 500
Nos 2
Type of pump Booster pump
Load in each pedestal(kg) 500
Type of pump Air blower Pressure filter (Domestic water system) Pressure filter (Domestic water system)
Load in each pedestal(kg) 2500 9375 9375
Type of pump Chlorinators
Load in each pedestal(kg) 100
Type of pump Chlorinators Dual media filter (CT) 1 Dual media filter (CT) 1 Air blowers
Load in each pedestal(kg) 100 5250 5250 2500
IN GRID 3 & 4 Pedestal type P4 IN GRID 4 & 5 Pedestal type P4
PEDESTALS BETWEEN GRID C & D IN GRID 2 & 3 Pedestal type P4 P3 P3
Nos 1 4 4
IN GRID 3 & 4 Pedestal type P5
Nos 4
IN GRID 4 & 5 Pedestal type P5 P6 P6 P4
Nos 2 4 4 2
DESIGN OF PEDESTALS: TYPE P1 Given data: Maximum axial load(P) =
57500 N
Size of the pedestal: Breadth of pedestal = Depth of pedestal = Height of pedestal = Design calculations: Factor of safety = Factored load (Pu) =
1100 mm 1100 mm 300 mm
1.5 86250 N
1100
1100mm
Gross area = 1210000 mm2 Pu/Ag = 0.071281 Hence provide 0.12% nominal reinforcement Ast = 1452 mm2 Hence provide 16nos of 12 dia bars @240mm c/c Lateral ties: Minimum dia of ties = 6 mm Pitch = 192 mm Hence provide 6 dia lateral tie @ 190 mm c/c
TYPE P2: Given data: Maximum axial load(P) =
26000 N
Size of the pedestal: Breadth of pedestal = Depth of pedestal = Height of pedestal =
800 mm 800 mm 300 mm 800
Design calculations: Factor of safety = Factored load (Pu) =
1.5 39000 N
800
Gross area = 640000 mm Pu/Ag = 0.060938 Hence provide 0.12% nominal reinforcement 2
Ast = 768 mm2 Hence provide 12 nos of 12 dia bars @220mm c/c Lateral ties: Minimum dia of ties = 6 mm Pitch = 192 mm Hence provide 6 dia lateral tie @ 190 mm c/c
TYPE P3: Given data: Maximum axial load(P) =
93750 N
Size of the pedestal: Breadth of pedestal = Depth of pedestal = Height of pedestal =
425 mm 425 mm 300 mm 425mm
Design calculations: Factor of safety = Factored load (Pu) =
1.5 140625 N
425mm
Gross area = 180625 mm Pu/Ag = 0.778547 Hence provide 0.12% nominal reinforcement 2
Ast = 216.75 mm2 Hence provide 8 nos of 12 dia bars @150mm c/c Lateral ties: Minimum dia of ties = 6 mm Pitch = 192 mm Hence provide 6 dia lateral tie @ 190 mm c/c
TYPE P4: Given data: Maximum axial load(P) =
5000 N
Size of the pedestal: Breadth of pedestal = Depth of pedestal = Height of pedestal =
500 mm 1250 mm 300 mm 1250mm
Design calculations: Factor of safety = Factored load (Pu) =
1.5 7500 N
500mm
Gross area = 625000 mm Pu/Ag = 0.012 Hence provide 0.12% nominal reinforcement 2
Ast = 750 mm2 Hence provide 10 nos of 12 dia bars @280mm c/c Lateral ties: Minimum dia of ties = 6 mm Pitch = 192 mm Hence provide 6 dia lateral tie @ 190 mm c/c
TYPE P5: Given data: Maximum axial load(P) =
1000 N
Size of the pedestal: Breadth of pedestal = Depth of pedestal = Height of pedestal = Design calculations: Factor of safety = Factored load (Pu) =
300 mm 600 mm 300 mm
1.5 1500 N
300mm
600mm
Gross area = 180000 mm2 Pu/Ag = 0.008333 Hence provide 0.12% nominal reinforcement Ast = 216 mm2 Hence provide 8 nos of 12 dia bars @225mm c/c Lateral ties: Minimum dia of ties = 6 mm Pitch = 192 mm Hence provide 6 dia lateral tie @ 190 mm c/c TYPE P6 Given data: Maximum axial load(P) =
52500 N
Size of the pedestal: Breadth of pedestal = Depth of pedestal = Height of pedestal = Design calculations: Factor of safety = Factored load (Pu) =
1180 mm 2180 mm 300 mm 2180mm 1.5 78750 N
Gross area = 2572400 mm2 Pu/Ag = 0.030613 Hence provide 0.12% nominal reinforcement
1180mm
1180mm
Ast = 3086.88 mm2 Hence provide 16 nos of 16 dia bars @240mm c/c and 6 nos of 12 dia bars @260 mm c/c Lateral ties: Minimum dia of ties = 6 mm Pitch = 192 mm Hence provide 6 dia lateral tie @ 190 mm c/c
TYPE P7 Given data: Maximum axial load(P) =
5000 N
Size of the pedestal: Breadth of pedestal = Depth of pedestal = Height of pedestal =
500 mm 1100 mm 300 mm
Design calculations: Factor of safety = Factored load (Pu) =
1.5 7500 N
Gross area = 550000 mm2 Pu/Ag = 0.013636 Hence provide 0.12% nominal reinforcement Ast = 660 mm2 Hence provide 10 nos of 12 dia bars @280mm c/c
1100
500mm
Lateral ties: Minimum dia of ties = 6 mm Pitch = 192 mm Hence provide 6 dia lateral tie @ 190 mm c/c TYPE P7 Given data: Maximum axial load(P) =
145000 N
Size of the pedestal: Breadth of pedestal = Depth of pedestal = Height of pedestal =
1000 mm 2000 mm 300 mm
2000 1180mm
Design calculations: Factor of safety = Factored load (Pu) =
1.5 217500 N
1000
Gross area = 2000000 mm Pu/Ag = 0.10875 Hence provide 0.12% nominal reinforcement 2
Ast = 2400 mm2 Hence provide 22 nos of 12 dia bars @265mm c/c Lateral ties: Minimum dia of ties = 6 mm Pitch = 192 mm Hence provide 6 dia lateral tie @ 190 mm c/c
Deign of reinforcement : Dual media pressure filters(Domestic water system): Given data: Maximum axial load(P) = 93750 N Size of the pedestal: Breadth of pedestal = Depth of pedestal = Height of pedestal =
500 mm 400 mm 300 mm
Design calculations: Factor of safety = 1.5 Factored load (Pu) = 140625 N Pu = 0.4 *σck *Ac +0.67*σy* Asc 400 Hence provide 0.12% nominal reinforcement Ast = 240 mm2 Hence provide 6 nos of 12 dia bars @200mm c/c
500
Lateral ties: Minimum dia of ties = 6 mm Pitch = 192 mm Hence provide 6 dia lateral tie @ 190 mm c/c Dual media filters(ct): Given data: Maximum axial load(P) =
52500 N
Size of the pedestal: Breadth of pedestal = Depth of pedestal = Height of pedestal =
500 mm 400 mm 500 mm 400
Design calculations: Factor of safety = Factored load (Pu) =
1.5 78750 N
500
Gross area = 200000 mm Pu/Ag = 0.39375 Hence provide 0.12% nominal reinforcement 2
Ast = 240 mm2 Hence provide 6 nos of 12 dia bars @200mm c/c Lateral ties: Minimum dia of ties = 6 mm Pitch = 192 mm Hence provide 6 dia lateral tie @ 190 mm c/c
Hydro pneumatic tank Given data: Maximum axial load(P) =
145000 N
Size of the pedestal: Breadth of pedestal = Depth of pedestal = Height of pedestal =
2350 mm 500 mm 1000 mm 500
Design calculations: Factor of safety = Factored load (Pu) =
1.5 217500 N
2350
Gross area = 1175000 mm Pu/Ag = 0.185106 Hence provide 0.12% nominal reinforcement 2
Ast = 1410 mm2 Hence provide 20 nos of 12 dia bars @280mm c/c Lateral ties: Minimum dia of ties = 6 mm Pitch = 192 mm Hence provide 6 dia lateral tie @ 190 mm c/c
DESIGN OF PEDESTALS:
CT MAKE UP PUMP Size of the base plate = Breadth of pedestal = Depth of pedestal = Height of pedestal =
650 x650x25 800 mm 800 mm 300 mm
Given data: Maximum axial load(P) = Grade of concrete(fck) = Grade of steel =
10730
N 30 Mpa 415 Mpa
Design calculations: Factor of safety = Design Factored load (Pu) =
1.5 16095 N Pu = 0.4 *σck *Ac +0.67*σy* Asc
Area of concrete (Ac) = Minimum Percentage of steel = Area of steel = Safe load Pu = Designed factored load(Pu) = Designed factored load(Pu) < Safe load
640000 mm2 0.15%
CHECK FOR BEARING STRESS: calculated bearing stress on the pedestal = load /area = Area of the pedestal(A1) = Area of the Base plate(A2) = Ratio (A1/A2) = Minimum allowable bearing stress = 0.45*fck = Maximum allowable bearing stress = 0.45*fck*sqrt(A1/A2) = CHECK: Hence the bearing check is satisfied Design of reinforcement: Area of steel = Hence provide 12 nos of 12 dia bars Lateral ties: Minimum dia of ties = Pitch = Hence provide 8 dia lateral tie @ 150 mm c/c
960 mm2
8 mm 192 mm
DM FEED PUMP Size of the base plate = Breadth of pedestal = Depth of pedestal = Height of pedestal = Given data: Maximum axial load(P) = Grade of concrete = Grade of steel =
(As per IS:456 clause 26.5.3.1)
960 mm2 7946928 N 16095 N Hence the section is adequate
650 x650x25 800 mm 800 mm 300 mm
17180
N 30 Mpa 415 Mpa
0.016766 640000 422500 1.230769 13.5 16.61538 16.61538
Mpa mm2 mm2 < 2 Mpa Mpa >
(From IS:456 clause 34.4)
0.016766 Mpa
Design calculations: Factor of safety = Design Factored load (Pu) =
1.5 25770 N Pu = 0.4 *σck *Ac +0.67*σy* Asc
Area of concrete (Ac) = Minimum Percentage of steel =
640000 mm2 0.15%
Area of steel = Safe load Pu = Designed factored load(Pu) = Designed factored load(Pu) < Safe load
CHECK FOR BEARING STRESS: Allowed Bearing pressure on the pedestal = load /area = Area of the pedestal(A1) = Area of the Base plate(A2) = Ratio (A1/A2) = Minimum allowable bearing stress =0.45*fck = Maximum allowable bearing stress = 0.45*fck*sqrt(A1/A2) = CHECK: Hence the bearing check is satisfied Design of reinforcement: Area of steel = Hence provide 12 nos of 12 dia bars
(As per IS:456 clause 26.5.3.1)
960 mm2 7946928 N 25770 N Hence the section is adequate
0.026844 640000 422500 1.230769 13.5 16.61538 16.61538
Mpa mm2 mm2 < 2 Mpa Mpa >
(From IS:456 clause 34.4)
0.026844 Mpa
0.0015 mm2
Lateral ties: Minimum dia of ties = Pitch = Hence provide 8 dia lateral tie @ 150 mm c/c
8 mm 192 mm
DOMESTIC WATER PUMP Size of the base plate = Breadth of pedestal = Depth of pedestal = Height of pedestal =
650 x650x25 800 mm 800 mm 300 mm
Given data: Maximum axial load(P) = Grade of concrete = Grade of steel =
15600
N 30 Mpa 415 Mpa
Design calculations: Factor of safety = Design Factored load (Pu) =
1.5 23400 N Pu = 0.4 *σck *Ac +0.67*σy* Asc
Area of concrete (Ac) = Minimum Percentage of steel = Area of steel = Safe load Pu = Designed factored load(Pu) = Designed factored load(Pu) < Safe load CHECK FOR BEARING STRESS: Allowed Bearing pressure on the pedestal = load /area = Area of the pedestal(A1) = Area of the Base plate(A2) = Ratio (A1/A2) =
640000 mm2 0.15%
(As per IS:456 clause 26.5.3.1)
960 mm 7946928 N 23400 N Hence the section is adequate 2
0.024375 640000 422500 1.230769
Mpa mm2 mm2 < 2
(From IS:456 clause 34.4)
Minimum allowable bearing stress =0.45*fck = Maximum allowable bearing stress = 0.45*fck*sqrt(A1/A2) = CHECK: Hence the bearing check is satisfied
13.5 Mpa 16.61538 Mpa 16.61538 >
0.024375 Mpa
Design of reinforcement: 960 mm2
Area of steel = Hence provde 12 nos of 12 mm dia bars Lateral ties: Minimum dia of ties = Pitch = Hence provide 8 dia lateral tie @ 150 mm c/c
8 mm 192 mm
JOCKEY PUMP Size of the base plate = Breadth of pedestal = Depth of pedestal = Height of pedestal =
525 x525 675 mm 675 mm 300 mm
Given data: Maximum axial load(P) = Grade of concrete = Grade of steel =
16000
N 30 Mpa 415 Mpa
Design calculations: Factor of safety = Design Factored load (Pu) =
1.5 24000 N Pu = 0.4 *σck *Ac +0.67*σy* Asc
Area of concrete (Ac) = Minimum Percentage of steel =
455625 mm2 0.15%
CHECK FOR BEARING STRESS: Allowed Bearing pressure on the pedestal = load /area = Area of the pedestal(A1) = Area of the Base plate(A2) = Ratio (A1/A2) = Minimum allowable bearing stress =0.45*fck = Maximum allowable bearing stress = 0.45*fck*sqrt(A1/A2) = CHECK: Hence the bearing check is satisfied Design of reinforcement: Area of steel = Hence provde 8 nos of 12 mm dia bars
(As per IS:456 clause 26.5.3.1)
683.4375 mm2 5657530 N 24000 N Hence the section is adequate
Area of steel = Safe load Pu = Designed factored load(Pu) = Designed factored load(Pu) < Safe load
683.4375 mm2
Lateral ties: Minimum dia of ties = Pitch = Hence provide 8 dia lateral tie @ 150 mm c/c
8 mm 192 mm
0.035117 455625 455625 1 13.5 13.5 13.5
Mpa mm2 mm2 < 2 Mpa Mpa >
(From IS:456 clause 34.4)
0.035117 Mpa
FW PUMP (MOTOR DRIVEN) Size of the base plate = Breadth of pedestal = Depth of pedestal = Height of pedestal =
850 x 650 1180 mm 1020 mm 300 mm
Given data: Maximum axial load(P) = Grade of concrete = Grade of steel =
39500
N 30 Mpa 415 Mpa
Design calculations: Factor of safety = Design Factored load (Pu) =
1.5 59250 N Pu = 0.4 *σck *Ac +0.67*σy* Asc
Assume percentage of steel as 0.8% Area of concrete (Ac) = Minimum Percentage of steel = Area of steel = Safe load Pu = Designed factored load(Pu) = Designed factored load(Pu) < Safe load
1203600 mm2 0.15%
CHECK FOR BEARING STRESS: Allowed Bearing pressure on the pedestal = load /area = Area of the pedestal(A1) = Area of the Base plate(A2) = Ratio (A1/A2) = Minimum allowable bearing stress =0.45*fck = Maximum allowable bearing stress = 0.45*fck*sqrt(A1/A2) = CHECK: Hence the bearing check is satisfied Design of reinforcement: Area of steel = Hence provde 20 nos of 12 mm dia bars Lateral ties: Minimum dia of ties = Pitch = Hence provide 8 dia lateral tie @ 150 mm c/c
1805.4 mm2
8 mm 192 mm
FW PUMP (DE DRIVEN) Size of the base plate = Breadth of pedestal = Depth of pedestal = Height of pedestal = Given data: Maximum axial load(P) = Grade of concrete = Grade of steel =
(As per IS:456 clause 26.5.3.1)
1805.4 mm2 14945191 N 59250 N Hence the section is adequate
850 x 650 1180 mm 1020 mm 300 mm
27000
N 30 Mpa 415 Mpa
0.032818 1203600 552500 1.475961 13.5 19.92548 19.92548
Mpa mm2 mm2 < 2 Mpa Mpa >
(From IS:456 clause 34.4)
0.032818 Mpa
Design calculations: Factor of safety = Design Factored load (Pu) =
1.5 40500 N Pu = 0.4 *σck *Ac +0.67*σy* Asc
Assume percentage of steel as 0.8% Area of concrete (Ac) = Minimum Percentage of steel = Area of steel = Safe load Pu = Designed factored load(Pu) = Designed factored load(Pu) < Safe load
1203600 mm2 0.15%
(As per IS:456 clause 26.5.3.1)
1805.4 mm2 14945191 N 40500 N Hence the section is adequate
CHECK FOR BEARING STRESS: Allowed Bearing pressure on the pedestal = load /area = Area of the pedestal(A1) = Area of the Base plate(A2) = Ratio (A1/A2) = Minimum allowable bearing stress =0.45*fck = Maximum allowable bearing stress = 0.45*fck*sqrt(A1/A2) = CHECK: Hence the bearing check is satisfied
0.022433 1203600 552500 1.475961 13.5 19.92548 19.92548
Mpa mm2 mm2 < 2 Mpa Mpa >
(From IS:456 clause 34.4)
0.022433 Mpa
Design of reinforcement: Area of steel = Hence provde 20 nos of 12 mm dia bars
1805.4 mm2
Lateral ties: Minimum dia of ties = Pitch = Hence provide 8 dia lateral tie @ 150 mm c/c
8 mm 192 mm
DECONTAMINATION PUMP Size of the base plate = Breadth of pedestal = Depth of pedestal = Height of pedestal =
650 x650x25 800 mm 800 mm 300 mm
Given data: Maximum axial load(P) = Grade of concrete = Grade of steel =
20000
N 30 Mpa 415 Mpa
Design calculations: Factor of safety = Design Factored load (Pu) =
1.5 30000 N Pu = 0.4 *σck *Ac +0.67*σy* Asc
Assume percentage of steel as 0.8% Area of concrete (Ac) = Minimum Percentage of steel = Area of steel = Safe load Pu = Designed factored load(Pu) = Designed factored load(Pu) < Safe load CHECK FOR BEARING STRESS: Allowed Bearing pressure on the pedestal = load /area = Area of the pedestal(A1) = Area of the Base plate(A2) =
640000 mm2 0.15%
(As per IS:456 clause 26.5.3.1)
960 mm2 7946928 N 30000 N Hence the section is adequate
0.03125 Mpa 640000 mm2 422500 mm2
Ratio (A1/A2) = Minimum allowable bearing stress =0.45*fck = Maximum allowable bearing stress = 0.45*fck*sqrt(A1/A2) = CHECK: Hence the bearing check is satisfied
1.230769 < 2 13.5 Mpa 16.61538 Mpa 16.61538 >
(From IS:456 clause 34.4)
0.03125 Mpa
Design of reinforcement: Area of steel = Hence provide 12 nos of 12 dia bars
960 mm2
Lateral ties: Minimum dia of ties = Pitch = Hence provide 8 dia lateral tie @ 150 mm c/c
8 mm 192 mm
DE DRIVEN Size of the base plate = Breadth of pedestal = Depth of pedestal = Height of pedestal =
2180x1180 2180 mm 1180 mm 300 mm
Given data: Maximum axial load(P) = Grade of concrete = Grade of steel =
27000
N 30 Mpa 415 Mpa
Design calculations: Factor of safety = Design Factored load (Pu) =
1.5 40500 N Pu = 0.4 *σck *Ac +0.67*σy* Asc
Area of concrete (Ac) = Minimum Percentage of steel = Area of steel = Safe load Pu = Designed factored load(Pu) = Designed factored load(Pu) < Safe load
2572400 mm2 0.15%
CHECK FOR BEARING STRESS: Allowed Bearing pressure on the pedestal = load /area = Area of the pedestal(A1) = Area of the Base plate(A2) = Ratio (A1/A2) = Minimum allowable bearing stress =0.45*fck = Maximum allowable bearing stress = 0.45*fck*sqrt(A1/A2) = CHECK: Hence the bearing check is satisfied Design of reinforcement: Area of steel = Hence provide 28 nos of 16 mm dia bars Lateral ties: Minimum dia of ties = Pitch = Hence provide 8 dia lateral tie @ 150 mm c/c
(As per IS:456 clause 26.5.3.1)
3858.6 mm2 31941684 N 40500 N Hence the section is adequate
3858.6 mm2
8 mm 256 mm
0.010496 2572400 2572400 1 13.5 13.5 13.5
Mpa
< 2 Mpa Mpa >
(From IS:456 clause 34.4)
0.010496 Mpa
Hydro pneumatic tank Size of Base plate = Breadth of pedestal = Depth of pedestal = Height of pedestal =
2250x400 2350 mm 500 mm 300 mm
Given data: Maximum axial load(P) = Grade of concrete = Grade of steel =
145000 N 30 Mpa 415 Mpa
Design calculations: Factor of safety = Design Factored load (Pu) =
1.5 217500 N Pu = 0.4 *σck *Ac +0.67*σy* Asc
Area of concrete (Ac) = Minimum Percentage of steel = Area of steel = Safe load Pu = Designed factored load(Pu) = Designed factored load(Pu) < Safe load
1175000 mm2 0.15%
CHECK FOR BEARING STRESS: Allowed Bearing pressure on the pedestal = load /area = Area of the pedestal(A1) = Area of the Base plate(A2) = Ratio (A1/A2) = Minimum allowable bearing stress =0.45*fck = Maximum allowable bearing stress = 0.45*fck*sqrt(A1/A2) = CHECK: Hence the bearing check is satisfied Design of reinforcement: Area of steel = Hence provide 20 nos of 12 dia bars Lateral ties: Minimum dia of ties = Pitch = Hence provide 8 dia lateral tie @ 150 mm c/c
1762.5 mm2
8 mm 192 mm
DUAL MEDIA FILTER Size of base plate = Breadth of pedestal = Depth of pedestal = Height of pedestal = Given data: Maximum axial load(P) = Grade of concrete = Grade of steel =
(As per IS:456 clause 26.5.3.1)
1762.5 mm2 14590063 N 217500 N Hence the section is adequate
370x350 400 mm 500 mm 300 mm
52500
N 30 Mpa 415 Mpa
0.123404 1175000 900000 1.142609 13.5 15.42522 15.42522
Mpa mm2 mm2 < 2 Mpa >
(From IS:456 clause 34.4)
0.123404 Mpa
Design calculations: Factor of safety = Design Factored load (Pu) =
1.5 78750 N Pu = 0.4 *σck *Ac +0.67*σy* Asc
Area of concrete (Ac) = Minimum Percentage of steel = Area of steel = Safe load Pu = Designed factored load(Pu) = Designed factored load(Pu) < Safe load
200000 mm2 0.15%
CHECK FOR BEARING STRESS: Allowed Bearing pressure on the pedestal = load /area = Area of the pedestal(A1) = Area of the Base plate(A2) = Ratio (A1/A2) = Minimum allowable bearing stress =0.45*fck = Maximum allowable bearing stress = 0.45*fck*sqrt(A1/A2) = CHECK: Hence the bearing check is satisfied Design of reinforcement: Area of steel = Hence provde 8 nos of 12mm dia bars Lateral ties: Minimum dia of ties = Pitch = Hence provide 8 dia lateral tie @ 150 mm c/c
(As per IS:456 clause 26.5.3.1)
300 mm2 2483415 N 78750 N Hence the section is adequate
300 mm2
8 mm 192 mm
0.2625 200000 129500 1.24274 13.5 16.77698 16.77698
Mpa mm2 mm2 < 2 Mpa Mpa >
(From IS:456 clause 34.4)
0.2625 Mpa
1 1 1
Type of pump CT make up pump DM Feed pump Domestic water pump
Load in each pedestal(kg) 1073 1718 1560
Nos 1 1
Type of pump Jockey pump FW pump motor driven
Static 1000(S) 1800(S)
Nos
IN GRID 3 & 4 Load(kg) Pedestal type P2 P1 IN GRID 4 &5 Load in each Pedestal type P6 P1 P7
Nos 2 2 2
Type of pump Diesel engine for FW pump FW pump DE driver FO tank
pedestal(kg) 1500 2700 500
Nos 1 1 1 1
Type of pump Diesel engine for FW pump FW pump DE driver FO tank FW pump motor driven
Load in each pedestal(kg) 800 2700 500 3950
Nos 1 1 1 1 1
Type of pump Jockey pump Domestic water pump (with motor) Dm feed pump ( with motor ) CT make up pump (with motor ) Decontainiation pump
Load in each pedestal(kg) 1600 1560 1718 1073 2000
IN GRID 5 & 6 Pedestal type P6 P1 P7 P1 IN GRID 5 & 6 Pedestal type P2 P1 P1 P1 P1
Dyamic 1600(D) 3950(D)
PEDESTALS BETWEEN GRID B &C IN GRID 2 & 3 Pedestal type P3 P3 P8
Nos Type of pump 1 Comp no.1 1 Comp no.2 2Hydro pnuematic tank
Load in each pedestal(kg) 1500 1500 14500
Nos 4
Type of pump Booster pump
Load in each pedestal(kg) 500
Nos 2
Type of pump Booster pump
Load in each pedestal(kg) 500
Type of pump Air blower Pressure filter (Domestic water system) Pressure filter (Domestic water system)
Load in each pedestal(kg) 2500 9375 9375
Type of pump Chlorinators
Load in each pedestal(kg) 100
Type of pump Chlorinators Dual media filter (CT) 1 Dual media filter (CT) 1 Air blowers
Load in each pedestal(kg) 100 5250 5250 2500
IN GRID 3 & 4 Pedestal type P4 IN GRID 4 & 5 Pedestal type P4
PEDESTALS BETWEEN GRID C & D IN GRID 2 & 3 Pedestal type P4 P3 P3
Nos 1 4 4
IN GRID 3 & 4 Pedestal type P5
Nos 4
IN GRID 4 & 5 Pedestal type P5 P6 P6 P4
Nos 2 4 4 2
DESIGN OF PEDESTALS: TYPE P1 Given data: Maximum axial load(P) =
57500 N
Size of the pedestal: Breadth of pedestal = Depth of pedestal = Height of pedestal = Design calculations: Factor of safety = Factored load (Pu) =
1100 mm 1100 mm 300 mm
1.5 86250 N
1100
1100mm
Gross area = 1210000 mm2 Pu/Ag = 0.071281 Hence provide 0.12% nominal reinforcement Ast = 1452 mm2 Hence provide 16nos of 12 dia bars @240mm c/c Lateral ties: Minimum dia of ties = 6 mm Pitch = 192 mm Hence provide 6 dia lateral tie @ 190 mm c/c
TYPE P2: Given data: Maximum axial load(P) =
26000 N
Size of the pedestal: Breadth of pedestal = Depth of pedestal = Height of pedestal =
800 mm 800 mm 300 mm 800
Design calculations: Factor of safety = Factored load (Pu) =
1.5 39000 N
800
Gross area = 640000 mm Pu/Ag = 0.060938 Hence provide 0.12% nominal reinforcement 2
Ast = 768 mm2 Hence provide 12 nos of 12 dia bars @220mm c/c Lateral ties: Minimum dia of ties = 6 mm Pitch = 192 mm Hence provide 6 dia lateral tie @ 190 mm c/c
TYPE P3: Given data: Maximum axial load(P) =
93750 N
Size of the pedestal: Breadth of pedestal = Depth of pedestal = Height of pedestal =
425 mm 425 mm 300 mm 425mm
Design calculations: Factor of safety = Factored load (Pu) =
1.5 140625 N
425mm
Gross area = 180625 mm Pu/Ag = 0.778547 Hence provide 0.12% nominal reinforcement 2
Ast = 216.75 mm2 Hence provide 8 nos of 12 dia bars @150mm c/c Lateral ties: Minimum dia of ties = 6 mm Pitch = 192 mm Hence provide 6 dia lateral tie @ 190 mm c/c
TYPE P4: Given data: Maximum axial load(P) =
5000 N
Size of the pedestal: Breadth of pedestal = Depth of pedestal = Height of pedestal =
500 mm 1250 mm 300 mm 1250mm
Design calculations: Factor of safety = Factored load (Pu) =
1.5 7500 N
500mm
Gross area = 625000 mm Pu/Ag = 0.012 Hence provide 0.12% nominal reinforcement 2
Ast = 750 mm2 Hence provide 10 nos of 12 dia bars @280mm c/c Lateral ties: Minimum dia of ties = 6 mm Pitch = 192 mm Hence provide 6 dia lateral tie @ 190 mm c/c
TYPE P5: Given data: Maximum axial load(P) =
1000 N
Size of the pedestal: Breadth of pedestal = Depth of pedestal = Height of pedestal = Design calculations: Factor of safety = Factored load (Pu) =
300 mm 600 mm 300 mm
1.5 1500 N
300mm
600mm
Gross area = 180000 mm2 Pu/Ag = 0.008333 Hence provide 0.12% nominal reinforcement Ast = 216 mm2 Hence provide 8 nos of 12 dia bars @225mm c/c Lateral ties: Minimum dia of ties = 6 mm Pitch = 192 mm Hence provide 6 dia lateral tie @ 190 mm c/c TYPE P6 Given data: Maximum axial load(P) =
52500 N
Size of the pedestal: Breadth of pedestal = Depth of pedestal = Height of pedestal = Design calculations: Factor of safety = Factored load (Pu) =
1180 mm 2180 mm 300 mm 2180mm 1.5 78750 N
Gross area = 2572400 mm2 Pu/Ag = 0.030613 Hence provide 0.12% nominal reinforcement
1180mm
1180mm
Ast = 3086.88 mm2 Hence provide 16 nos of 16 dia bars @240mm c/c and 6 nos of 12 dia bars @260 mm c/c Lateral ties: Minimum dia of ties = 6 mm Pitch = 192 mm Hence provide 6 dia lateral tie @ 190 mm c/c
TYPE P7 Given data: Maximum axial load(P) =
5000 N
Size of the pedestal: Breadth of pedestal = Depth of pedestal = Height of pedestal =
500 mm 1100 mm 300 mm
Design calculations: Factor of safety = Factored load (Pu) =
1.5 7500 N
Gross area = 550000 mm2 Pu/Ag = 0.013636 Hence provide 0.12% nominal reinforcement Ast = 660 mm2 Hence provide 10 nos of 12 dia bars @280mm c/c
1100
500mm
Lateral ties: Minimum dia of ties = 6 mm Pitch = 192 mm Hence provide 6 dia lateral tie @ 190 mm c/c TYPE P7 Given data: Maximum axial load(P) =
145000 N
Size of the pedestal: Breadth of pedestal = Depth of pedestal = Height of pedestal =
1000 mm 2000 mm 300 mm
2000 1180mm
Design calculations: Factor of safety = Factored load (Pu) =
1.5 217500 N
1000
Gross area = 2000000 mm Pu/Ag = 0.10875 Hence provide 0.12% nominal reinforcement 2
Ast = 2400 mm2 Hence provide 22 nos of 12 dia bars @265mm c/c Lateral ties: Minimum dia of ties = 6 mm Pitch = 192 mm Hence provide 6 dia lateral tie @ 190 mm c/c
Deign of reinforcement : Dual media pressure filters(Domestic water system): Given data: Maximum axial load(P) = 93750 N Size of the pedestal: Breadth of pedestal = Depth of pedestal = Height of pedestal =
500 mm 400 mm 300 mm
Design calculations: Factor of safety = 1.5 Factored load (Pu) = 140625 N Pu = 0.4 *σck *Ac +0.67*σy* Asc 400 Hence provide 0.12% nominal reinforcement Ast = 240 mm2 Hence provide 6 nos of 12 dia bars @200mm c/c
500
Lateral ties: Minimum dia of ties = 6 mm Pitch = 192 mm Hence provide 6 dia lateral tie @ 190 mm c/c Dual media filters(ct): Given data: Maximum axial load(P) =
52500 N
Size of the pedestal: Breadth of pedestal = Depth of pedestal = Height of pedestal =
500 mm 400 mm 500 mm 400
Design calculations: Factor of safety = Factored load (Pu) =
1.5 78750 N
500
Gross area = 200000 mm Pu/Ag = 0.39375 Hence provide 0.12% nominal reinforcement 2
Ast = 240 mm2 Hence provide 6 nos of 12 dia bars @200mm c/c Lateral ties: Minimum dia of ties = 6 mm Pitch = 192 mm Hence provide 6 dia lateral tie @ 190 mm c/c
Hydro pneumatic tank Given data: Maximum axial load(P) =
145000 N
Size of the pedestal: Breadth of pedestal = Depth of pedestal = Height of pedestal =
2350 mm 500 mm 1000 mm 500
Design calculations: Factor of safety = Factored load (Pu) =
1.5 217500 N
2350
Gross area = 1175000 mm Pu/Ag = 0.185106 Hence provide 0.12% nominal reinforcement 2
Ast = 1410 mm2 Hence provide 20 nos of 12 dia bars @280mm c/c Lateral ties: Minimum dia of ties = 6 mm Pitch = 192 mm Hence provide 6 dia lateral tie @ 190 mm c/c
DESIGN OF PEDESTALS:
CT MAKE UP PUMP Size of the base plate = Breadth of pedestal = Depth of pedestal = Height of pedestal =
650 x650x25 800 mm 800 mm 300 mm
Given data: Maximum axial load(P) = Grade of concrete(fck) = Grade of steel =
10730
N 30 Mpa 415 Mpa
Design calculations: Factor of safety = Design Factored load (Pu) =
1.5 16095 N Pu = 0.4 *σck *Ac +0.67*σy* Asc
Area of concrete (Ac) = Minimum Percentage of steel = Area of steel = Safe load Pu = Designed factored load(Pu) = Designed factored load(Pu) < Safe load
640000 mm2 0.15%
CHECK FOR BEARING STRESS: calculated bearing stress on the pedestal = load /area = Area of the pedestal(A1) = Area of the Base plate(A2) = Ratio (A1/A2) = Minimum allowable bearing stress = 0.45*fck = Maximum allowable bearing stress = 0.45*fck*sqrt(A1/A2) = CHECK: Hence the bearing check is satisfied Design of reinforcement: Area of steel = Hence provide 12 nos of 12 dia bars Lateral ties: Minimum dia of ties = Pitch = Hence provide 8 dia lateral tie @ 150 mm c/c
960 mm2
8 mm 192 mm
DM FEED PUMP Size of the base plate = Breadth of pedestal = Depth of pedestal = Height of pedestal = Given data: Maximum axial load(P) = Grade of concrete = Grade of steel =
(As per IS:456 clause 26.5.3.1)
960 mm2 7946928 N 16095 N Hence the section is adequate
650 x650x25 800 mm 800 mm 300 mm
17180
N 30 Mpa 415 Mpa
0.016766 640000 422500 1.230769 13.5 16.61538 16.61538
Mpa mm2 mm2 < 2 Mpa Mpa >
(From IS:456 clause 34.4)
0.016766 Mpa
Design calculations: Factor of safety = Design Factored load (Pu) =
1.5 25770 N Pu = 0.4 *σck *Ac +0.67*σy* Asc
Area of concrete (Ac) = Minimum Percentage of steel =
640000 mm2 0.15%
Area of steel = Safe load Pu = Designed factored load(Pu) = Designed factored load(Pu) < Safe load
CHECK FOR BEARING STRESS: Allowed Bearing pressure on the pedestal = load /area = Area of the pedestal(A1) = Area of the Base plate(A2) = Ratio (A1/A2) = Minimum allowable bearing stress =0.45*fck = Maximum allowable bearing stress = 0.45*fck*sqrt(A1/A2) = CHECK: Hence the bearing check is satisfied Design of reinforcement: Area of steel = Hence provide 12 nos of 12 dia bars
(As per IS:456 clause 26.5.3.1)
960 mm2 7946928 N 25770 N Hence the section is adequate
0.026844 640000 422500 1.230769 13.5 16.61538 16.61538
Mpa mm2 mm2 < 2 Mpa Mpa >
(From IS:456 clause 34.4)
0.026844 Mpa
0.0015 mm2
Lateral ties: Minimum dia of ties = Pitch = Hence provide 8 dia lateral tie @ 150 mm c/c
8 mm 192 mm
DOMESTIC WATER PUMP Size of the base plate = Breadth of pedestal = Depth of pedestal = Height of pedestal =
650 x650x25 800 mm 800 mm 300 mm
Given data: Maximum axial load(P) = Grade of concrete = Grade of steel =
15600
N 30 Mpa 415 Mpa
Design calculations: Factor of safety = Design Factored load (Pu) =
1.5 23400 N Pu = 0.4 *σck *Ac +0.67*σy* Asc
Area of concrete (Ac) = Minimum Percentage of steel = Area of steel = Safe load Pu = Designed factored load(Pu) = Designed factored load(Pu) < Safe load CHECK FOR BEARING STRESS: Allowed Bearing pressure on the pedestal = load /area = Area of the pedestal(A1) = Area of the Base plate(A2) = Ratio (A1/A2) =
640000 mm2 0.15%
(As per IS:456 clause 26.5.3.1)
960 mm 7946928 N 23400 N Hence the section is adequate 2
0.024375 640000 422500 1.230769
Mpa mm2 mm2 < 2
(From IS:456 clause 34.4)
Minimum allowable bearing stress =0.45*fck = Maximum allowable bearing stress = 0.45*fck*sqrt(A1/A2) = CHECK: Hence the bearing check is satisfied
13.5 Mpa 16.61538 Mpa 16.61538 >
0.024375 Mpa
Design of reinforcement: 960 mm2
Area of steel = Hence provde 12 nos of 12 mm dia bars Lateral ties: Minimum dia of ties = Pitch = Hence provide 8 dia lateral tie @ 150 mm c/c
8 mm 192 mm
JOCKEY PUMP Size of the base plate = Breadth of pedestal = Depth of pedestal = Height of pedestal =
525 x525 675 mm 675 mm 300 mm
Given data: Maximum axial load(P) = Grade of concrete = Grade of steel =
16000
N 30 Mpa 415 Mpa
Design calculations: Factor of safety = Design Factored load (Pu) =
1.5 24000 N Pu = 0.4 *σck *Ac +0.67*σy* Asc
Area of concrete (Ac) = Minimum Percentage of steel =
455625 mm2 0.15%
CHECK FOR BEARING STRESS: Allowed Bearing pressure on the pedestal = load /area = Area of the pedestal(A1) = Area of the Base plate(A2) = Ratio (A1/A2) = Minimum allowable bearing stress =0.45*fck = Maximum allowable bearing stress = 0.45*fck*sqrt(A1/A2) = CHECK: Hence the bearing check is satisfied Design of reinforcement: Area of steel = Hence provde 8 nos of 12 mm dia bars
(As per IS:456 clause 26.5.3.1)
683.4375 mm2 5657530 N 24000 N Hence the section is adequate
Area of steel = Safe load Pu = Designed factored load(Pu) = Designed factored load(Pu) < Safe load
683.4375 mm2
Lateral ties: Minimum dia of ties = Pitch = Hence provide 8 dia lateral tie @ 150 mm c/c
8 mm 192 mm
0.035117 455625 455625 1 13.5 13.5 13.5
Mpa mm2 mm2 < 2 Mpa Mpa >
(From IS:456 clause 34.4)
0.035117 Mpa
FW PUMP (MOTOR DRIVEN) Size of the base plate = Breadth of pedestal = Depth of pedestal = Height of pedestal =
850 x 650 1180 mm 1020 mm 300 mm
Given data: Maximum axial load(P) = Grade of concrete = Grade of steel =
39500
N 30 Mpa 415 Mpa
Design calculations: Factor of safety = Design Factored load (Pu) =
1.5 59250 N Pu = 0.4 *σck *Ac +0.67*σy* Asc
Assume percentage of steel as 0.8% Area of concrete (Ac) = Minimum Percentage of steel = Area of steel = Safe load Pu = Designed factored load(Pu) = Designed factored load(Pu) < Safe load
1203600 mm2 0.15%
CHECK FOR BEARING STRESS: Allowed Bearing pressure on the pedestal = load /area = Area of the pedestal(A1) = Area of the Base plate(A2) = Ratio (A1/A2) = Minimum allowable bearing stress =0.45*fck = Maximum allowable bearing stress = 0.45*fck*sqrt(A1/A2) = CHECK: Hence the bearing check is satisfied Design of reinforcement: Area of steel = Hence provde 20 nos of 12 mm dia bars Lateral ties: Minimum dia of ties = Pitch = Hence provide 8 dia lateral tie @ 150 mm c/c
1805.4 mm2
8 mm 192 mm
FW PUMP (DE DRIVEN) Size of the base plate = Breadth of pedestal = Depth of pedestal = Height of pedestal = Given data: Maximum axial load(P) = Grade of concrete = Grade of steel =
(As per IS:456 clause 26.5.3.1)
1805.4 mm2 14945191 N 59250 N Hence the section is adequate
850 x 650 1180 mm 1020 mm 300 mm
27000
N 30 Mpa 415 Mpa
0.032818 1203600 552500 1.475961 13.5 19.92548 19.92548
Mpa mm2 mm2 < 2 Mpa Mpa >
(From IS:456 clause 34.4)
0.032818 Mpa
Design calculations: Factor of safety = Design Factored load (Pu) =
1.5 40500 N Pu = 0.4 *σck *Ac +0.67*σy* Asc
Assume percentage of steel as 0.8% Area of concrete (Ac) = Minimum Percentage of steel = Area of steel = Safe load Pu = Designed factored load(Pu) = Designed factored load(Pu) < Safe load
1203600 mm2 0.15%
(As per IS:456 clause 26.5.3.1)
1805.4 mm2 14945191 N 40500 N Hence the section is adequate
CHECK FOR BEARING STRESS: Allowed Bearing pressure on the pedestal = load /area = Area of the pedestal(A1) = Area of the Base plate(A2) = Ratio (A1/A2) = Minimum allowable bearing stress =0.45*fck = Maximum allowable bearing stress = 0.45*fck*sqrt(A1/A2) = CHECK: Hence the bearing check is satisfied
0.022433 1203600 552500 1.475961 13.5 19.92548 19.92548
Mpa mm2 mm2 < 2 Mpa Mpa >
(From IS:456 clause 34.4)
0.022433 Mpa
Design of reinforcement: Area of steel = Hence provde 20 nos of 12 mm dia bars
1805.4 mm2
Lateral ties: Minimum dia of ties = Pitch = Hence provide 8 dia lateral tie @ 150 mm c/c
8 mm 192 mm
DECONTAMINATION PUMP Size of the base plate = Breadth of pedestal = Depth of pedestal = Height of pedestal =
650 x650x25 800 mm 800 mm 300 mm
Given data: Maximum axial load(P) = Grade of concrete = Grade of steel =
20000
N 30 Mpa 415 Mpa
Design calculations: Factor of safety = Design Factored load (Pu) =
1.5 30000 N Pu = 0.4 *σck *Ac +0.67*σy* Asc
Assume percentage of steel as 0.8% Area of concrete (Ac) = Minimum Percentage of steel = Area of steel = Safe load Pu = Designed factored load(Pu) = Designed factored load(Pu) < Safe load CHECK FOR BEARING STRESS: Allowed Bearing pressure on the pedestal = load /area = Area of the pedestal(A1) = Area of the Base plate(A2) =
640000 mm2 0.15%
(As per IS:456 clause 26.5.3.1)
960 mm2 7946928 N 30000 N Hence the section is adequate
0.03125 Mpa 640000 mm2 422500 mm2
Ratio (A1/A2) = Minimum allowable bearing stress =0.45*fck = Maximum allowable bearing stress = 0.45*fck*sqrt(A1/A2) = CHECK: Hence the bearing check is satisfied
1.230769 < 2 13.5 Mpa 16.61538 Mpa 16.61538 >
(From IS:456 clause 34.4)
0.03125 Mpa
Design of reinforcement: Area of steel = Hence provide 12 nos of 12 dia bars
960 mm2
Lateral ties: Minimum dia of ties = Pitch = Hence provide 8 dia lateral tie @ 150 mm c/c
8 mm 192 mm
DE DRIVEN Size of the base plate = Breadth of pedestal = Depth of pedestal = Height of pedestal =
2180x1180 2180 mm 1180 mm 300 mm
Given data: Maximum axial load(P) = Grade of concrete = Grade of steel =
27000
N 30 Mpa 415 Mpa
Design calculations: Factor of safety = Design Factored load (Pu) =
1.5 40500 N Pu = 0.4 *σck *Ac +0.67*σy* Asc
Area of concrete (Ac) = Minimum Percentage of steel = Area of steel = Safe load Pu = Designed factored load(Pu) = Designed factored load(Pu) < Safe load
2572400 mm2 0.15%
CHECK FOR BEARING STRESS: Allowed Bearing pressure on the pedestal = load /area = Area of the pedestal(A1) = Area of the Base plate(A2) = Ratio (A1/A2) = Minimum allowable bearing stress =0.45*fck = Maximum allowable bearing stress = 0.45*fck*sqrt(A1/A2) = CHECK: Hence the bearing check is satisfied Design of reinforcement: Area of steel = Hence provide 28 nos of 16 mm dia bars Lateral ties: Minimum dia of ties = Pitch = Hence provide 8 dia lateral tie @ 150 mm c/c
(As per IS:456 clause 26.5.3.1)
3858.6 mm2 31941684 N 40500 N Hence the section is adequate
3858.6 mm2
8 mm 256 mm
0.010496 2572400 2572400 1 13.5 13.5 13.5
Mpa
< 2 Mpa Mpa >
(From IS:456 clause 34.4)
0.010496 Mpa
Hydro pneumatic tank Size of Base plate = Breadth of pedestal = Depth of pedestal = Height of pedestal =
2250x400 2350 mm 500 mm 300 mm
Given data: Maximum axial load(P) = Grade of concrete = Grade of steel =
145000 N 30 Mpa 415 Mpa
Design calculations: Factor of safety = Design Factored load (Pu) =
1.5 217500 N Pu = 0.4 *σck *Ac +0.67*σy* Asc
Area of concrete (Ac) = Minimum Percentage of steel = Area of steel = Safe load Pu = Designed factored load(Pu) = Designed factored load(Pu) < Safe load
1175000 mm2 0.15%
CHECK FOR BEARING STRESS: Allowed Bearing pressure on the pedestal = load /area = Area of the pedestal(A1) = Area of the Base plate(A2) = Ratio (A1/A2) = Minimum allowable bearing stress =0.45*fck = Maximum allowable bearing stress = 0.45*fck*sqrt(A1/A2) = CHECK: Hence the bearing check is satisfied Design of reinforcement: Area of steel = Hence provide 20 nos of 12 dia bars Lateral ties: Minimum dia of ties = Pitch = Hence provide 8 dia lateral tie @ 150 mm c/c
1762.5 mm2
8 mm 192 mm
DUAL MEDIA FILTER Size of base plate = Breadth of pedestal = Depth of pedestal = Height of pedestal = Given data: Maximum axial load(P) = Grade of concrete = Grade of steel =
(As per IS:456 clause 26.5.3.1)
1762.5 mm2 14590063 N 217500 N Hence the section is adequate
370x350 400 mm 500 mm 300 mm
52500
N 30 Mpa 415 Mpa
0.123404 1175000 900000 1.142609 13.5 15.42522 15.42522
Mpa mm2 mm2 < 2 Mpa >
(From IS:456 clause 34.4)
0.123404 Mpa
Design calculations: Factor of safety = Design Factored load (Pu) =
1.5 78750 N Pu = 0.4 *σck *Ac +0.67*σy* Asc
Area of concrete (Ac) = Minimum Percentage of steel = Area of steel = Safe load Pu = Designed factored load(Pu) = Designed factored load(Pu) < Safe load
200000 mm2 0.15%
CHECK FOR BEARING STRESS: Allowed Bearing pressure on the pedestal = load /area = Area of the pedestal(A1) = Area of the Base plate(A2) = Ratio (A1/A2) = Minimum allowable bearing stress =0.45*fck = Maximum allowable bearing stress = 0.45*fck*sqrt(A1/A2) = CHECK: Hence the bearing check is satisfied Design of reinforcement: Area of steel = Hence provde 8 nos of 12mm dia bars Lateral ties: Minimum dia of ties = Pitch = Hence provide 8 dia lateral tie @ 150 mm c/c
(As per IS:456 clause 26.5.3.1)
300 mm2 2483415 N 78750 N Hence the section is adequate
300 mm2
8 mm 192 mm
0.2625 200000 129500 1.24274 13.5 16.77698 16.77698
Mpa mm2 mm2 < 2 Mpa Mpa >
(From IS:456 clause 34.4)
0.2625 Mpa
Related Documents 3h463d
Pedestal Design 5i241u
October 2019 25
Square Concrete Pedestal Design Calculation Sample 51p5o
December 2019 85
Manual Bi Image Pedestal 161265
August 2021 0
Metode Pekerjaan Pondasi Pedestal 6o6jf
October 2020 0
Subestacion Tipo Pedestal 6k6a13
April 2021 0