Phy1331 Assignment 1 Solutions.pdf 4j511j

STUDENT #: _________________ NAME: _________________________ GROUP:________________________

UNIVERSITY OF OTTAWA Principles of Physics PHY1321/31 Fall 2016 Dr. A. Czajkowski

ASSIGNMENT 1: Pressure, Temperature, Ideal Gas Equation Released: Sept 16 Due: Sept 23 1

HS teacher duplicated Torricelli's barometer using a mineral oil, of density 1530kg/m3, as the working liquid. What was the height h of the oil column for normal atmospheric pressure ,

#$ '.)'*×') # ℎ = %& = = 6.76𝑚 ('/*)0&/23 )(5.60&/278

Since P0 = ρ gh 2

6PM

A U-tube of uniform cross-sectional area, open to the atmosphere, is partially filled with mercury. Water is then poured into both arms. If the equilibrium configuration of the tube is as shown in, with h2 = 1.00 cm, determine the value of h1.

Let h be the height of the water column added to the right side of the U–tube. Then when equilibrium is reached, the situation is as shown in the sketch at right. Now consider two points, A and B shown in the sketch, at the level of the water–mercury interface. By Pascal’s Principle, the absolute pressure at B is the same as that at A. But,



PA = P0 + rw gh + rHg gh2 and PB = P0 + rw g ( h1 + h + h2 ) .

h1

Thus, from PA = PB , rw h1 + rw h + rw h2 = rw h + rHg h2 , or

3

a) b) c)



h

é rHg ù h1 = ê - 1ú h2 = ( 13.6 - 1)(1.00 cm) = 12.6 cm ë rw û

B

h2

a) Show that 1 mole of any gas at atmospheric pressure and at 0o C is taking 22.4 liters of volume (b) Show that the density of an ideal gas occupying a volume V is given by PM/RT, where M is the molar mass. (c) Determine the density of nitrogen gas at atmospheric pressure and 20.0°C. /use opposite side of this page to show all your calculations)

pV = nRT ⇒ (101000)V = (1)(8.31)(273) = 0.0224m 3 = 22.4l m pM m pM pV = nRT ⇒ pV = RT ⇒ = ⇒ρ= M RT V RT => ')'*)) ().)86) 0& ρ= = = 1.165 3 ?@

(6.*')(85*)

2

water

A

Mercury

UNIVERSITY OF OTTAWA Principles of Physics PHY1321/31 Fall 2016 Dr. A. Czajkowski

ASSIGNMENT 1: CONT 4

STUDENT #: _________________ NAME: _________________________ GROUP:________________________

192 grams of oxygen and 80 grams of hydrogen gas occupy separate, equal sections of 200 liter tank. The divide is removed and the gases are allowed to mix and react with each other. The temperature is kept constant at 130 °C, throughout the process a) find the pressure of each gas in the separate containers b) find the pressure after the reaction ends.

There are 6 moles of molecular oxygen gas in the first section, so

𝑃D 𝑉D = 𝑛𝑅𝑇 ⇒ 𝑃D 𝑂8 =

K 6.*' M)* ).'

𝑃𝑎 = 200935.8𝑃𝑎 = 201𝑘𝑃𝑎

There are 40 moles of molecular hydrogen gas in the first section, so

𝑃D 𝑉D = 𝑛𝑅𝑇 ⇒ 𝑃D 𝐻8 =

M) 6.*' M)* ).'

𝑃𝑎 = 1339572𝑃𝑎 = 1340𝑘𝑃𝑎

B) after the reaction there will be 12moles of steam and 28 moles of molecular hydrogen in a 200 liter container. The final pressure of will be a sum of the partial pressures taken independently (12) (8.31) (403) 𝑃W 𝑉W = 𝑛𝑅𝑇 ⇒ 𝑃W 𝐻8 𝑂 = 𝑃𝑎 = 200935.8𝑃𝑎 = 201𝑘𝑃𝑎

0.2

𝑃W 𝑉W = 𝑛𝑅𝑇 ⇒ 𝑃W 𝐻8 =

5



(28) (8.31) (403) 𝑃𝑎 = 468850.2𝑃𝑎 = 469𝒌𝑷𝒂 0.2

A telescope forms an image of part of a cluster of stars on a square silicon chargecoupled detector (CCD) chip 2.00 cm on each side. A star field is focused on the CCD when it is first turned on and its temperature is 27.0°C. The star field contains 5 432 stars scattered uniformly. To make the detector more sensitive, it is cooled to –173°C. How many star images then fit onto the chip? The average coefficient of linear expansion of silicon is 4.68´10–6 (°C)–1.

Δ𝑆 = 𝛾𝑆Δ𝑇 = 2𝛼𝑆Δ𝑇 = 2 4.68 ∙ 10`K ∙ 4 ∙ −200 𝑐𝑚 8 = −0.007488𝑐𝑚 8 𝑆W = 𝑆D + ΔS = 3.992512𝑐𝑚 8

𝑁W =

𝑁 5432 𝑆W = 3.992512 = 5421.83 = 5421 𝑓𝑢𝑙𝑙 𝑠𝑡𝑎𝑟𝑠 𝑆D 4